Chapter 11, Problem 11.63SP

Interpretation Introduction

Interpretation:

The molality of the $\text{16}\text{.0 mass \%}$ solution of Sulphuric acid has to be calculated.

Concept introduction:

Molality of a solution also called as molal concentration can be defined as the mass of solute in grams to the mass of the solvent in kilograms. It can be given by the equation,

$\text{Molality(mol}{\text{kg}}^{\text{-1}}\text{)=}\frac{\text{Mass}\text{of}\text{solue(in}\text{g)}}{\text{Mass}\text{of}\text{solvent(in}\text{kg)}}$