Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
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Chapter 11, Problem 100QRT

(a)

Interpretation Introduction

Interpretation:

Whether the given reaction is zeroth, first-, or second-order by using the units of the rate constant has to be determined.

Concept Introduction:

  orderofreactionunitofrateconstant0molL1time11time12mol1Ltime1

(a)

Expert Solution
Check Mark

Explanation of Solution

The rate constant of the reaction is 0.68s1. So the given reaction is first order because the unit of its rate constant is time1.

(b)

Interpretation Introduction

Interpretation:

The mass of azomethane remains after 5.0s has to be calculated.

Concept Introduction:

The integrated rate equation for first order reaction is given below.

  λt=ln[A]o[A]t

Where,

    λ is the rate constant/ decay constant

    t is the time taken to change the concentration from [A]oto[A]t

    [A]o is the initial concentration of A

    [A]t is the final concentration A

Half-life of a first order reaction can be calculated using following equation.

    t12=0.693λ

(b)

Expert Solution
Check Mark

Answer to Problem 100QRT

The mass of azomethane remains after 5.0s is 0.65g.

Explanation of Solution

Given,

    λ=0.68s1.

    t=5.0s

    [A]o=2g58.08g/mol2L=0.17M

The mass of azomethane remains after 5.0s can be calculated as follows,

    λt=ln[A]o[A]t(0.68s1)×(5.0s)=ln0.17M[A]t3.4=ln0.17M[A]t0.17M[A]t=e3.4[A]t=0.17Me3.4=5.6×10-3M.

The concentration of azomethane remains is 5.6×10-3M.

Therefore the mass of azomethane remains can be calculated as follows,

    Molarity=massmalecularmassvolume5.6×10-3M=mass58.08g/mol2Lmass=(5.6×10-3M)×(2L)×(58.08g/mol)=0.65g.

The mass of azomethane remains after 5.0s is 0.65g.

(c)

Interpretation Introduction

Interpretation:

The time taken for the azomethane to drop from 2gto0.24g has to be calculated.

Concept Introduction:

Refer to part (b).

(c)

Expert Solution
Check Mark

Answer to Problem 100QRT

The time taken for the concentration to drop from 2gto0.24g is 3.09s.

Explanation of Solution

Given,

  λ=0.68s1

    [A]o=2g58.08g/mol2L=0.017M

    [A]t=0.24g58.08g/mol2L=2.066×10-3M

The time taken for the azomethane to drop from 2gto0.24g can be calculated as follows,

    t=1λln[A]o[A]t=10.68s1ln(0.017M2.066×10-3M)=3.09s.

The time taken for the concentration to drop from 2gto0.24g is 3.09s.

(d)

Interpretation Introduction

Interpretation:

The mass of nitrogen found in the flask after 0.5s has to be calculated.

Concept Introduction:

Refer to part (b).

(d)

Expert Solution
Check Mark

Answer to Problem 100QRT

The mass of nitrogen remaining in the flask after 0.5s is 0.3gN2.

Explanation of Solution

Mass of C2H6N2 remained after 0.5s can be calculated using following equation.

  t=1λln[A]o[A]t

Here mass is proportional to concentration.  So instead of concentration mass can be taken for calculation as follows,

    t=1λln[A]o[A]tln[A]t=λt+ln[A]o=(0.68s1)(0.5s)+ln(2g)massof[A]t=e0.4=1.4g.

1.4g of C2H6N2 is remaining in the system.

Amount of C2H6N2 used can be calculated as follows,

  C2H6N2used=initialC2H6N2finalC2H6N2=2g1.4g=0.6g.

Hence mass of nitrogen remaining in the flask can be calculated as follows,

    0.6g×1molC2H6N258.1gC2H6N2×1molN21molC2H6N2×28.02gN21molN2=0.3gN2.

The mass of nitrogen remaining in the flask after 0.5s is 0.3gN2.

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Chapter 11 Solutions

Chemistry: The Molecular Science

Ch. 11.3 - Prob. 11.6PSPCh. 11.3 - Prob. 11.7PSPCh. 11.4 - Prob. 11.6ECh. 11.4 - Prob. 11.7CECh. 11.4 - Prob. 11.8PSPCh. 11.4 - Prob. 11.8CECh. 11.5 - Prob. 11.9PSPCh. 11.5 - The frequency factor A is 6.31 108 L mol1 s1 and...Ch. 11.6 - Prob. 11.10CECh. 11.7 - Prob. 11.11ECh. 11.7 - The Raschig reaction produces the industrially...Ch. 11.7 - Prob. 11.12ECh. 11.8 - The oxidation of thallium(I) ion by cerium(IV) ion...Ch. 11.9 - Prob. 11.11PSPCh. 11.9 - Prob. 11.14CECh. 11 - An excellent way to make highly pure nickel metal...Ch. 11 - Prob. 1QRTCh. 11 - Prob. 2QRTCh. 11 - Prob. 3QRTCh. 11 - Prob. 4QRTCh. 11 - Prob. 5QRTCh. 11 - Prob. 6QRTCh. 11 - Prob. 7QRTCh. 11 - Prob. 8QRTCh. 11 - Prob. 9QRTCh. 11 - Prob. 10QRTCh. 11 - Prob. 11QRTCh. 11 - Cyclobutane can decompose to form ethylene: The...Ch. 11 - Prob. 13QRTCh. 11 - Prob. 14QRTCh. 11 - For the reaction 2NO2(g)2NO(g)+O2(g) make...Ch. 11 - Prob. 16QRTCh. 11 - Prob. 17QRTCh. 11 - Ammonia is produced by the reaction between...Ch. 11 - Prob. 19QRTCh. 11 - Prob. 20QRTCh. 11 - The reaction of CO(g) + NO2(g) is second-order in...Ch. 11 - Nitrosyl bromide, NOBr, is formed from NO and Br2....Ch. 11 - Prob. 23QRTCh. 11 - Prob. 24QRTCh. 11 - Prob. 25QRTCh. 11 - For the reaction these data were obtained at 1100...Ch. 11 - Prob. 27QRTCh. 11 - Prob. 28QRTCh. 11 - Prob. 29QRTCh. 11 - Prob. 30QRTCh. 11 - Prob. 31QRTCh. 11 - Prob. 32QRTCh. 11 - For the reaction of phenyl acetate with water the...Ch. 11 - When phenacyl bromide and pyridine are both...Ch. 11 - The compound p-methoxybenzonitrile N-oxide, which...Ch. 11 - Prob. 36QRTCh. 11 - Radioactive gold-198 is used in the diagnosis of...Ch. 11 - Prob. 38QRTCh. 11 - Prob. 39QRTCh. 11 - Prob. 40QRTCh. 11 - Prob. 41QRTCh. 11 - Prob. 42QRTCh. 11 - Prob. 43QRTCh. 11 - Prob. 44QRTCh. 11 - Prob. 45QRTCh. 11 - Prob. 46QRTCh. 11 - Prob. 47QRTCh. 11 - Prob. 48QRTCh. 11 - Prob. 49QRTCh. 11 - Prob. 50QRTCh. 11 - Prob. 51QRTCh. 11 - Prob. 52QRTCh. 11 - For the reaction of iodine atoms with hydrogen...Ch. 11 - Prob. 54QRTCh. 11 - The activation energy Ea is 139.7 kJ mol1 for the...Ch. 11 - Prob. 56QRTCh. 11 - Prob. 57QRTCh. 11 - Prob. 58QRTCh. 11 - Prob. 59QRTCh. 11 - Prob. 60QRTCh. 11 - Prob. 61QRTCh. 11 - Prob. 62QRTCh. 11 - Prob. 63QRTCh. 11 - Which of the reactions in Question 62 would (a)...Ch. 11 - Prob. 65QRTCh. 11 - Prob. 66QRTCh. 11 - Prob. 67QRTCh. 11 - Prob. 68QRTCh. 11 - Prob. 69QRTCh. 11 - Prob. 70QRTCh. 11 - Prob. 71QRTCh. 11 - For the reaction the rate law is Rate=k[(CH3)3CBr]...Ch. 11 - Prob. 73QRTCh. 11 - Prob. 74QRTCh. 11 - Prob. 75QRTCh. 11 - For this reaction mechanism, write the chemical...Ch. 11 - Prob. 77QRTCh. 11 - Prob. 78QRTCh. 11 - Prob. 79QRTCh. 11 - When enzymes are present at very low...Ch. 11 - Prob. 81QRTCh. 11 - The reaction is catalyzed by the enzyme succinate...Ch. 11 - Prob. 83QRTCh. 11 - Many biochemical reactions are catalyzed by acids....Ch. 11 - Prob. 85QRTCh. 11 - Prob. 86QRTCh. 11 - Prob. 87QRTCh. 11 - Prob. 88QRTCh. 11 - Prob. 89QRTCh. 11 - Prob. 90QRTCh. 11 - Prob. 91QRTCh. 11 - Prob. 92QRTCh. 11 - Prob. 93QRTCh. 11 - Prob. 94QRTCh. 11 - Nitryl fluoride is an explosive compound that can...Ch. 11 - Prob. 96QRTCh. 11 - Prob. 97QRTCh. 11 - For a reaction involving the decomposition of a...Ch. 11 - Prob. 99QRTCh. 11 - Prob. 100QRTCh. 11 - Prob. 101QRTCh. 11 - This graph shows the change in concentration as a...Ch. 11 - Prob. 103QRTCh. 11 - Prob. 104QRTCh. 11 - Prob. 105QRTCh. 11 - Prob. 106QRTCh. 11 - Prob. 107QRTCh. 11 - Prob. 108QRTCh. 11 - Prob. 109QRTCh. 11 - Prob. 110QRTCh. 11 - Prob. 111QRTCh. 11 - Prob. 112QRTCh. 11 - Prob. 113QRTCh. 11 - Prob. 114QRTCh. 11 - Prob. 115QRTCh. 11 - Prob. 116QRTCh. 11 - Prob. 118QRTCh. 11 - Prob. 119QRTCh. 11 - In a time-resolved picosecond spectroscopy...Ch. 11 - If you know some calculus, derive the integrated...Ch. 11 - If you know some calculus, derive the integrated...Ch. 11 - (Section 11-5) A rule of thumb is that for a...Ch. 11 - Prob. 11.BCPCh. 11 - Prob. 11.CCPCh. 11 - Prob. 11.DCP
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