Chemist is testing by running the reaction when different R groups on each alcohol carbons are used; the correct statement has to be identified. Concept Introduction: Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows, Step 1: Add proton (protonation of Pinacol using acid catalyst). Step 2: Break a bond to give a stable molecules or ions (formation of carbocation). Step 3: 1, 2-shift (migration of substituent from α- to β- carbon). Step 4: deprotonation occurs (take a proton away).

Question

a. Determine the electrochemical potential of the following cell using E°Mg2+/Mg = -2.362 V. Mg | Mg2+ (a=104) || H* (a = 4) | H2 (p = 0.5 bar) | Pt b. A galvanic chain consists of Co²+ / Co and Ag+ / Ag half-cells with EºCo²+/Co = -0.282 V and Eº Ag+/Ag = 0.799 V. Determine which half-cell will be reduced and which one will be oxidised. Furthermore, calculate the electrochemical potential as well as the equilibrium constant of the whole cell at i. [Co²+] = 0.1 M and [Ag+] = 0.5 M ii. [Co²+] = 0.001 M and [Ag*] = 1.5 M

Answer 1

Question

Chapter 10.7, Problem GQ

Interpretation Introduction

Interpretation:

Chemist is testing by running the reaction when different R groups on each alcohol carbons are used; the correct statement has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

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