Synthetic intermediates A and B has to be drawn. Concept Introduction: Conversion of alcohol into haloalkane: Conversion of primary and secondary alcohols to Chloroalkane is thionyl chloride. The reaction is carried out in the presence of base such as pyridine or trimethylamine. The reaction of an alcohol with thionyl chloride is the formation of an alkyl Chlorosulfite that converts hydroxide ion (poor leaving group) into Chlorosulfite (good leaving group). Nucleophilic displacement of this leaving group gives product. Leaving group: Leaving group can be any groups or atoms that get detached from either neutral or charged organic compounds. The stability of the leaving group is to stabilize the electron density that results from heterolysis cleavage of bond.

Question

8 00 6 = 10 10 Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than unstable, you can pick any of them to redraw.) Check OH stable HO stable Ounstable unstable O OH stable unstable OH 80 F6 F5 stable Ounstable X Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ཀྭ་ A F7 매 F8 F9 4 F10

Answer 1

Question

Chapter 10, Problem 10.58P

Interpretation Introduction

Interpretation:

Synthetic intermediates A and B has to be drawn.

Concept Introduction:

Conversion of alcohol into haloalkane:

Conversion of primary and secondary alcohols to Chloroalkane is thionyl chloride. The reaction is carried out in the presence of base such as pyridine or trimethylamine.

The reaction of an alcohol with thionyl chloride is the formation of an alkyl Chlorosulfite that converts hydroxide ion (poor leaving group) into Chlorosulfite (good leaving group). Nucleophilic displacement of this leaving group gives product.

Leaving group: Leaving group can be any groups or atoms that get detached from either neutral or charged organic compounds. The stability of the leaving group is to stabilize the electron density that results from heterolysis cleavage of bond.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

8 00 6 = 10 10 Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than unstable, you can pick any of them to redraw.) Check OH stable HO stable Ounstable unstable O OH stable unstable OH 80 F6 F5 stable Ounstable X Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ཀྭ་ A F7 매 F8 F9 4 F10

Just try completing it and it should be straightforward according to the professor and TAs.

The grading is not on correctness, so if you can just get to the correct answers without perfectionism that would be great. They care about the steps and reasoning and that you did something. I asked for an extension, but was denied the extension.