In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified. Concept Introduction: Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows, Step 1: Add proton (protonation of Pinacol using acid catalyst). Step 2: Break a bond to give a stable molecules or ions (formation of carbocation). Step 3: 1, 2-shift (migration of substituent from α- to β- carbon). Step 4: deprotonation occurs (take a proton away).

Question

Want to see the full answer?

Answer 1

Question

Chapter 10.7, Problem AQ

Interpretation Introduction

Interpretation:

In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Don't used Ai solution

Answer 2

Question

Chapter 10.7, Problem AQ

Interpretation Introduction

Interpretation:

In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 10.7, Problem AQ

Interpretation Introduction

Interpretation:

In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 10.7, Problem AQ

Interpretation Introduction

Interpretation:

In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 10.7, Problem AQ

Interpretation Introduction

Interpretation:

In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

Answer 6

Chapter 10.7, Problem AQ

Interpretation Introduction

Interpretation:

In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

Answer 7

Chapter 10.7, Problem AQ

Interpretation Introduction

Interpretation:

In the Pinacol rearrangement name of the intermediate with a positive charge on carbon has to be identified.

Concept Introduction:

Pinacol rearrangement: For all glycols Pinacol rearrangement occurs. Unsymmetrical vicinal diols reveal that –OH group that becomes protonated and leaves in the one that gives rise to more stable carbocation. Acid-catalyzed conversion of Pinacol to pinacolone followed by four step mechanism as follows,

Step 1: Add proton (protonation of Pinacol using acid catalyst).

Step 2: Break a bond to give a stable molecules or ions (formation of carbocation).

Step 3: 1, 2-shift (migration of substituent from α- to β- carbon).

Step 4: deprotonation occurs (take a proton away).

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 10.1 - Write IUPAC names for these alcohols and include...Ch. 10.1 - Classify each alcohol as primary, secondary, or...Ch. 10.1 - Write IUPAC names for these unsaturated alcohols.Ch. 10.2 - Arrange these compounds in order of increasing...Ch. 10.2 - Prob. 10.5P Ch. 10.4 - Predict the position of equilibrium for this...Ch. 10.5 - Show how to convert (R)-2-pentanol to...Ch. 10.6 - Draw structural formulas for the alkenes formed by...Ch. 10.6 - Propose a mechanism to account for this...Ch. 10.7 - Propose a mechanism to account for the following...

Solution Summary: The author explains the Pinacol rearrangement reaction mechanism and the correct option for identifying the intermediate with a positive charge on carbon.

Concept explainers

Want to see the full answer?

Chapter 10 Solutions