Explanation Consider the figure below. Resolve all the forces into parallel and perpendicular components. Consider an axis which is perpendicular to the page and passing through the upper end of tibia. Let T y , ω y , and F y be the non-zero forces about the mentioned axis. The magnitude of force T y from figure is. T y = T sin 25.0 ° The magnitude of force ω y form figure is. ω y = ( 30.0 N ) sin 40.0 ° = 19.3 N The magnitude of force F y form figure 1 is. F y = ( 12.5 N ) sin 40.0 ° = 8.03 N The net torque about an axis perpendicular to the page and passing through the upper end of tibia is zero. ∑ τ = 0 (I) The net torque is due to these three forces T y , ω y , and F y

Principles of Physics: A Calculus-Based Text

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ISBN: 9781133104261

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 10, Problem 77P

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The tension at angle 25.0° with the tibia.

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Chapter 10, Problem 76P

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The tension at angle 25.0 ° with the tibia.

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