Explanation Consider the figure given below. Let n 0 be the normal force at point O , m b be the mass of the beam. Write the expression for net torque. ∑ τ = − n 0 ( l 2 + d ) + m 1 g ( l 2 + d ) + m b g d − m 2 g x (I) Here, l is the length of the beam, d is the distance from center of gravity to the point P , m 1 is the mass of the block at right end of the beam, m 2 is the mass of the block at the left end of the beam, and x is the distance between the mass m 2 and point P . At some points torque acts in clockwise direction and in some other point s torque acts in anticlockwise direction. Hence the net torque will be zero. ∑ τ = − n 0 ( l 2 + d ) + m 1 g ( l 2 + d ) + m b g d − m 2 g x = 0 (II) It is required to find the distance x at which the normal force at point O become zero. Substitute, 0 for n 0 in equation (II), and rearrange to obtain an expression for x

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Chapter 10, Problem 30P

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The reason why it is impossible to adjust the position of the second mass along the length of the beam until the normal force acting on the beam is zero.

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Chapter 10, Problem 29P

Chapter 10, Problem 31P

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The reason why it is impossible to adjust the position of the second mass along the length of the beam until the normal force acting on the beam is zero.

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The reason why it is impossible to adjust the position of the second mass along the length of the beam until the normal force acting on the beam is zero.

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