Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Question
Chapter 10, Problem 10.88QE
Interpretation Introduction
Interpretation:
The ground state electronic configuration, the bond order, and the stability of
Concept Introduction:
The bond order is the number of electrons pairs shared between two atoms in the formation of the bond.
Bond order
Where,
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The average bond energy (enthalpy) for a C=C double bond is 614 kJ/molkJ/mol and that of a C−C single bond is 348 kJ/molkJ/mol. If it takes
4.42×10−19
J/molecule
to break the C=C double bond. What is the longest wavelength λ of light that will provide photons of sufficient energy to break the π bond and cause the isomerization?
Express your answer numerically in nanometers.
- Draw Lewis structures for each of the following. Give the total number of valence electrons,
select from the lists the number of Regions of Electron Density (REDs) around the central atom,
the molecular shape, and the bond angles.
- Do not put covalent bonds between metals and nonmetals.
- Put brackets around anions to show both charge and quantity
REDS
0, no central atom
2
3
4
Shapes
tetrahedral
pyramidal
bent
trigonal planar
linear
diatomic
monatomic ions
Bond Angles
109.5°
120°
180°
none, no central atom
1. H2CCI2
valence e =
REDS =
shape=
bond angles =
2. NC13
valence e =
REDs =
shape=
bond angles =
3. CS2
valence e =
REDS =
shape=
bond angles =
dihydrogen carbon dichloride
nitrogen trichloride
carbon disulfide
- Draw Lewis structures for each of the following. Give the total number of valence electrons, select from
the lists the number of Regions of Electron Density (REDs) around the central atom, the molecular shape,
and the bond angles.
- Do not put covalent bonds between metals and nonmetals.
- Put brackets around anions to show both charge and quantity
REDS
0, no central atom
2
3
4
Shapes
tetrahedral
pyramidal
bent
trigonal planar
linear
diatomic
monatomic ions
Bond Angles
109.5°
120°
180°
none, no central atom
6. OCI2
valence e =
REDS =
shape=
bond angles
=
oxygen dichloride
7. P2S4
valence e =
REDs at each central atom =
shape at each central atom =
bond angles =
diphosphorus tetrasulfide
dicarbon tetrachloride
8. C2C14
valence e =
REDs at each central atom =
shape at each central atom =
bond angles =
Chapter 10 Solutions
Chemistry: Principles and Practice
Ch. 10 - Prob. 10.1QECh. 10 - Prob. 10.2QECh. 10 - Prob. 10.3QECh. 10 - Prob. 10.4QECh. 10 - Prob. 10.5QECh. 10 - Prob. 10.6QECh. 10 - Prob. 10.7QECh. 10 - Prob. 10.8QECh. 10 - Prob. 10.9QECh. 10 - Prob. 10.10QE
Ch. 10 - Which atomic orbitals overlap to form the bonds in...Ch. 10 - Prob. 10.12QECh. 10 - Identify the hybrid orbitals used by boron in BCl3...Ch. 10 - Identify the hybrid orbitals used by antimony in...Ch. 10 - Prob. 10.15QECh. 10 - Prob. 10.16QECh. 10 - Prob. 10.17QECh. 10 - Prob. 10.18QECh. 10 - Prob. 10.19QECh. 10 - Prob. 10.20QECh. 10 - Compare and contrast the molecular orbital and...Ch. 10 - Describe the bonding in molecular orbital terms...Ch. 10 - Prob. 10.23QECh. 10 - Prob. 10.24QECh. 10 - Prob. 10.25QECh. 10 - Prob. 10.26QECh. 10 - Prob. 10.27QECh. 10 - Prob. 10.28QECh. 10 - Prob. 10.29QECh. 10 - Prob. 10.30QECh. 10 - Prob. 10.31QECh. 10 - Prob. 10.32QECh. 10 - Prob. 10.33QECh. 10 - Prob. 10.34QECh. 10 - Prob. 10.35QECh. 10 - Prob. 10.36QECh. 10 - Prob. 10.37QECh. 10 - Prob. 10.38QECh. 10 - Prob. 10.39QECh. 10 - Use the VSEPR model to predict the bond angles...Ch. 10 - Prob. 10.41QECh. 10 - Prob. 10.42QECh. 10 - For each of the following molecules, complete the...Ch. 10 - Prob. 10.44QECh. 10 - Prob. 10.45QECh. 10 - Prob. 10.46QECh. 10 - Indicate which molecules are polar and which are...Ch. 10 - Prob. 10.48QECh. 10 - Indicate which of the following molecules are...Ch. 10 - Prob. 10.50QECh. 10 - Prob. 10.51QECh. 10 - Prob. 10.52QECh. 10 - Prob. 10.53QECh. 10 - Prob. 10.54QECh. 10 - Prob. 10.55QECh. 10 - Prob. 10.56QECh. 10 - Prob. 10.57QECh. 10 - Prob. 10.58QECh. 10 - Prob. 10.59QECh. 10 - Prob. 10.60QECh. 10 - Prob. 10.61QECh. 10 - Prob. 10.62QECh. 10 - Prob. 10.63QECh. 10 - Prob. 10.64QECh. 10 - Prob. 10.65QECh. 10 - Prob. 10.66QECh. 10 - Prob. 10.67QECh. 10 - Prob. 10.68QECh. 10 - Prob. 10.69QECh. 10 - Prob. 10.70QECh. 10 - Prob. 10.71QECh. 10 - Prob. 10.72QECh. 10 - Identify the orbitals on each of the atoms that...Ch. 10 - Prob. 10.74QECh. 10 - Prob. 10.75QECh. 10 - How many sigma bonds and how many pi bonds are...Ch. 10 - Give the hybridization of each central atom in the...Ch. 10 - Prob. 10.78QECh. 10 - Prob. 10.79QECh. 10 - Prob. 10.80QECh. 10 - Prob. 10.81QECh. 10 - Predict the hybridization at each central atom in...Ch. 10 - Prob. 10.83QECh. 10 - Tetrafluoroethylene, C2F4, is used to produce...Ch. 10 - Prob. 10.85QECh. 10 - Prob. 10.86QECh. 10 - Prob. 10.87QECh. 10 - Prob. 10.88QECh. 10 - Prob. 10.89QECh. 10 - Prob. 10.90QECh. 10 - Prob. 10.91QECh. 10 - Prob. 10.92QECh. 10 - Prob. 10.93QECh. 10 - Prob. 10.94QECh. 10 - Prob. 10.95QECh. 10 - Prob. 10.96QECh. 10 - Prob. 10.97QECh. 10 - Prob. 10.98QECh. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - Prob. 10.102QECh. 10 - Prob. 10.103QECh. 10 - Prob. 10.104QECh. 10 - Prob. 10.105QECh. 10 - Following are the structures of three isomers of...Ch. 10 - The ions ClF2 and ClF2+ have both been observed....Ch. 10 - Aspirin, or acetylsalicylic acid, has the formula...Ch. 10 - Aspartame is a compound that is 200 times sweeter...Ch. 10 - Prob. 10.110QECh. 10 - Prob. 10.111QECh. 10 - Calcium cyanamide, CaNCN, is used both to kill...Ch. 10 - Histidine is an essential amino acid that the body...Ch. 10 - Formamide, HC(O)NH2, is prepared at high pressures...Ch. 10 - Prob. 10.115QECh. 10 - Prob. 10.116QECh. 10 - Prob. 10.117QECh. 10 - Prob. 10.118QECh. 10 - Prob. 10.119QECh. 10 - Prob. 10.120QECh. 10 - Prob. 10.121QECh. 10 - Prob. 10.122QECh. 10 - Prob. 10.123QECh. 10 - Prob. 10.124QECh. 10 - Two compounds have the formula S2F2. Disulfur...Ch. 10 - Prob. 10.126QECh. 10 - Prob. 10.127QE
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- Best Lewis Formula and Molecular Geometry A student writes the Lewis electron-dot formula for the carbonate anion, CO32, as a Does this Lewis formula obey the octet rule? Explain. What are the formal charges on the atoms? Try describing the bonding for this formula in valence bond terms. Do you have any difficulty doing this? b Does this Lewis formula give a reasonable description of the electron structure, or is there a better one? If there is a better Lewis formula, write it down and explain why it is better. c The same student writes the following resonance description for CO2: Is there something wrong with this description? (What would you predict as the geometries of these formulas?) d Is one or the other formula a better description? Could a value for the dipole moment help you decide? e Can you write a Lewis formula that gives an even better description of CO2? Explain your answer.arrow_forward- Draw Lewis structures for each of the following. Give the total number of valence electrons, select from the lists the number of Regions of Electron Density (REDs) around the central atom, the molecular shape, and the bond angles. - Do not put covalent bonds between metals and nonmetals. - Put brackets around anions to show both charge and quantity REDS 0, no central atom 2 3 4 Shapes tetrahedral pyramidal bent trigonal planar linear diatomic monatomic ions Bond Angles 109.5° 120° 180° none, no central atom 9. Na3P valence e = REDs = shape= bond angles = 10. AI(NO3)3 valence e = REDs = shape = bond angles = sodium phosphide aluminum nitrate For nitratearrow_forwardDraw Lewis structure for OPF, (P is the central atom). Write down all possible resonance structures, including formal charges. Draw the geometry of the ion. Indicate the hybridization of the central atom and type of orbitals involved in x bonding on both bonded atoms.arrow_forward
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