Organic Chemistry, Ebook And Single-course Homework Access
Organic Chemistry, Ebook And Single-course Homework Access
6th Edition
ISBN: 9781319085841
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 10, Problem 10.41AP
Interpretation Introduction

(a)

Interpretation:

The structure of seven-carbon tertiary alcohol which yields a single alkene after acid-catalyzed dehydration is to be stated.

Concept introduction:

The dehydration of alcohol in the presence of acid catalyst results in the formation of an alkene with the removal of one molecule of water. Dehydration of alcohol is a type of β- elimination reaction, in which beta hydrogen is eliminated from the alcohol molecule. If all beta hydrogen in alcohol is equivalent, then only single alkene will be the major product.

Interpretation Introduction

(b)

Interpretation:

The structure of alcohol that, after acid-catalyzed dehydration yields an alkene and after the ozonolysis followed with (CH3)2S, gives only benzaldehyde is to be stated.

Concept introduction:

The dehydration of alcohol in the presence of acid catalyst results in the formation of an alkene with the removal of one molecule of water. Dehydration of alcohol is a type of β- elimination reaction, in which beta hydrogen is eliminated from the alcohol molecule. If all beta hydrogen in alcohol is equivalent, then only single alkene will be the major product.

Interpretation Introduction

(c)

Interpretation:

The structure of alcohol that gives the same product when it reacts with KMnO4 as it obtained from the ozonolysis of trans3,6dimethyl4octene followed by treatment with H2O2 is to be stated.

Concept introduction:

Potassium permanganate (KMnO4) is a useful oxidizing agent, which can oxidize primary alcohol to carboxylic acid in the presence of basic solution but not used in secondary alcohol to ketones because ketones react further with alkaline permanganate solution. The oxidative ozonolysis of alkene also produces a carboxylic acid.

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)
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