ORGANIC CHEMISTRY
ORGANIC CHEMISTRY
5th Edition
ISBN: 9781259977596
Author: SMITH
Publisher: MCG
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Chapter 1, Problem 1.7P

Draw a Lewis structure for each ion.

a. CH 3 O b. HC 2 c. ( CH 3 NH 3 ) + d. ( CH 3 NH )

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation: The Lewis structure for CH3O is to be drawn.

Concept Introduction: Lewis structures are electron dot representations for molecules. These structures show the bonding between the atoms or molecules and the lone pairs of electrons. The arrangement of valence electrons among the atoms in a molecule is represented by its Lewis structure.

Answer to Problem 1.7P

The Lewis structure for CH3O is shown in Figure 2.

Explanation of Solution

In the given molecular formula, CH3O, the atoms are arranged as,

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  1

Figure 1

The total valence electrons in CH3O are,

(1C×4e)+(3H×1e)+(1O×6e)+1e(negativecharge)=4e+3e+6e+1e=14e

The bonds and lone pairs are added to form CC, CH, CO bonds. The Lewis structure for CH3O is shown below.

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  2

Figure 2

Conclusion

The Lewis structure for CH3O is shown in Figure 2.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation: The Lewis structure for HC2 is to be drawn.

Concept Introduction: Lewis structures are electron dot representations for molecules. These structures show the bonding between the atoms or molecules and the lone pairs of electrons. The arrangement of valence electrons among the atoms in a molecule is represented by its Lewis structure.

Answer to Problem 1.7P

The Lewis structure of HC2 is shown in Figure 5.

Explanation of Solution

In the given molecular formula, HC2, the atoms are arranged as,

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  3

Figure 3

The total valence electrons in HC2 are,

(2C×4e)+(1H×1e)+1e(negativecharge)=8e+1e+1e=10e

The bonds and lone pairs are added to form CC and CH bonds but one C has incomplete octet. Lone pairs is converted into bond pairs which forms triple bond as given below

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  4

Figure 4

The Lewis structure for HC2 is shown below.

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  5

Figure 5

Conclusion

The Lewis structure of HC2 is shown in Figure 5.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation: The Lewis structure for (CH3NH3)+ is to be drawn.

Concept Introduction: Lewis structures are electron dot representations for molecules. These structures show the bonding between the atoms or molecules and the lone pairs of electrons. The arrangement of valence electrons among the atoms in a molecule is represented by its Lewis structure.

Answer to Problem 1.7P

The Lewis structure of (CH3NH3)+ is shown Figure 7.

Explanation of Solution

In the given molecular formula, (CH3NH3)+, the atoms are arranged as,

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  6

Figure 6

The total valence electrons in (CH3NH3)+ are,

(1C×4e)+(6H×1e)+(1N×5e)1e(positivecharge)=4e+6e+5e1e=14e

The bonds and lone pairs are added to form CN, CH, NH bonds. The Lewis structure for (CH3NH3)+ is shown below.

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  7

Figure 7

Conclusion

The Lewis structure of (CH3NH3)+ is shown Figure 7.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation: The Lewis structure for (CH3NH) is to be drawn.

Concept Introduction: Lewis structures are electron dot representations for molecules. These structures show the bonding between the atoms or molecules and the lone pairs of electrons. These structures can be drawn for any covalently bonded molecules.

Answer to Problem 1.7P

The Lewis structure of (CH3NH) is shown in Figure 9.

Explanation of Solution

The given molecular formula, (CH3NH) in which atoms are arranged as,

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  8

Figure 8

The total valence electrons in (CH3NH) are,

(1C×4e)+(4H×1e)+(1N×5e)+1e(negativecharge)=4e+4e+5e+1e=14e

The bonds and lone pairs are added to form C-N, C-H, N-H bonds. The Lewis structure for (CH3NH) is shown below.

ORGANIC CHEMISTRY, Chapter 1, Problem 1.7P , additional homework tip  9

Figure 9

Conclusion

The Lewis structure of (CH3NH) is shown in Figure 9.

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Chapter 1 Solutions

ORGANIC CHEMISTRY

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