Chapter 1, Problem 1.63P

Interpretation Introduction

(a)

Interpretation: Hydrogen atoms and non bonded electron pairs in ${\text{C}}_{\text{6}}{\text{H}}_{\text{5}}^{-}$ are to be drawn.

Concept introduction: A charge on a carbon atom takes the place of one hydrogen atom. The charge determines the number of lone pairs. Negatively charged carbon atoms have one lone pair and positively charged carbon atoms have none.

Interpretation Introduction

(b)

Interpretation: Hydrogen atoms and non bonded electron pairs in ${\text{CH}}_{\text{3}}{\text{COCH}}_{\text{2}}^{-}$ are to be drawn.

Concept introduction: A charge on a carbon atom takes the place of one hydrogen atom. The charge determines the number of lone pairs. Negatively charged carbon atoms have one lone pair and positively charged carbon atoms have none.

Interpretation Introduction

(c)

Interpretation: Hydrogen atoms and non bonded electron pairs in given ion is to be drawn.

Concept introduction: A charge on a carbon atom takes the place of one hydrogen atom. The charge determines the number of lone pairs. Negatively charged carbon atoms have one lone pair and positively charged carbon atoms have none.

Interpretation Introduction

(d)

Interpretation: Hydrogen atoms and non bonded electron pairs in given species are to be drawn.

Concept introduction: A charge on a carbon atom takes the place of one hydrogen atom. The charge determines the number of lone pairs. Negatively charged carbon atoms have one lone pair and positively charged carbon atoms have none.

Interpretation Introduction

(e)

Interpretation: Hydrogen atoms and non bonded electron pairs in given ion are to be drawn.

Concept introduction: A charge on a carbon atom takes the place of one hydrogen atom. The charge determines the number of lone pairs. Negatively charged carbon atoms have one lone pair and positively charged carbon atoms have none.