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You perform electrophoresis of 3 proteins, Hemoglobin (pl: 6.8), DNA Polymerase (pl: 5.2) and Porcine pepsin (pl: 1.0) in a Tris-Glycine buffer (pH 5.2). (pl = Isoelectric point). Select which of the following is true. O All proteins will migrate at the same rate O All proteins will migrate at the same direction Porcine pepsin will migrate toward the electrode Porcine pepsin will not migrate and stay in the well O O O O

You perform electrophoresis of 3 proteins, Hemoglobin (pl: 6.8), DNA Polymerase (pl: 5.2) and Porcine pepsin (pl: 1.0) in a Tris-Glycine buffer (pH 5.2). (pl = Isoelectric point). Select which of the following is true. O All proteins will migrate at the same rate O All proteins will migrate at the same direction Porcine pepsin will migrate toward the electrode Porcine pepsin will not migrate and stay in the well O O O O

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
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**Electrophoresis of Proteins Experiment Analysis** In this experiment, we explore the electrophoresis of three proteins: Hemoglobin, DNA Polymerase, and Porcine Pepsin. The isoelectric points (pI), where each protein has no net charge, are as follows: Hemoglobin (pI: 6.8), DNA Polymerase (pI: 5.2), and Porcine Pepsin (pI: 1.0). The medium utilized for this experiment is a Tris-Glycine buffer with a pH value of 5.2. **Electrophoresis Conditions and Expected Outcomes:** Electrophoresis is a technique used to separate proteins based on their size and charge. In this context, since the buffer pH is 5.2, the behavior of each protein can be predicted as follows: 1. **Hemoglobin (pI: 6.8)**: At pH 5.2, which is lower than its pI, Hemoglobin will have a net positive charge. Therefore, it will migrate towards the negative electrode (cathode). 2. **DNA Polymerase (pI: 5.2)**: Its pI is equal to the buffer pH. In such a scenario, DNA Polymerase will have no net charge and, thus, will not migrate significantly in the electric field. 3. **Porcine Pepsin (pI: 1.0)**: Since pH 5.2 is higher than its pI, Porcine Pepsin will have a net negative charge, causing it to migrate towards the positive electrode (anode). ### Question Presented: Select which of the following statements is true based on the described conditions: - All proteins will migrate at the same rate - All proteins will migrate in the same direction - Porcine Pepsin will migrate towards the electrode - Porcine Pepsin will not migrate and stay in the well **Answer Analysis:** Given the behavior of each protein at pH 5.2: - **Statement 1**: Incorrect, as proteins migrate at different rates based on their charges. - **Statement 2**: Incorrect, as the direction of migration depends on the charge of the protein. - **Statement 3**: Correct, Porcine Pepsin will indeed migrate towards the positive electrode. - **Statement 4**: Incorrect, Porcine
Transcribed Image Text:**Electrophoresis of Proteins Experiment Analysis** In this experiment, we explore the electrophoresis of three proteins: Hemoglobin, DNA Polymerase, and Porcine Pepsin. The isoelectric points (pI), where each protein has no net charge, are as follows: Hemoglobin (pI: 6.8), DNA Polymerase (pI: 5.2), and Porcine Pepsin (pI: 1.0). The medium utilized for this experiment is a Tris-Glycine buffer with a pH value of 5.2. **Electrophoresis Conditions and Expected Outcomes:** Electrophoresis is a technique used to separate proteins based on their size and charge. In this context, since the buffer pH is 5.2, the behavior of each protein can be predicted as follows: 1. **Hemoglobin (pI: 6.8)**: At pH 5.2, which is lower than its pI, Hemoglobin will have a net positive charge. Therefore, it will migrate towards the negative electrode (cathode). 2. **DNA Polymerase (pI: 5.2)**: Its pI is equal to the buffer pH. In such a scenario, DNA Polymerase will have no net charge and, thus, will not migrate significantly in the electric field. 3. **Porcine Pepsin (pI: 1.0)**: Since pH 5.2 is higher than its pI, Porcine Pepsin will have a net negative charge, causing it to migrate towards the positive electrode (anode). ### Question Presented: Select which of the following statements is true based on the described conditions: - All proteins will migrate at the same rate - All proteins will migrate in the same direction - Porcine Pepsin will migrate towards the electrode - Porcine Pepsin will not migrate and stay in the well **Answer Analysis:** Given the behavior of each protein at pH 5.2: - **Statement 1**: Incorrect, as proteins migrate at different rates based on their charges. - **Statement 2**: Incorrect, as the direction of migration depends on the charge of the protein. - **Statement 3**: Correct, Porcine Pepsin will indeed migrate towards the positive electrode. - **Statement 4**: Incorrect, Porcine
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