Passage 1 (Questions 1-4)Human immunodeficiency virus 1 (HIV-1) protease inhibitors have beensuccessful at lowering HIV-1 levels and blocking the onset of acquiredimmune deficiency syndrome (AIDS). However, because HIV-1 mutantsare developing resistance to current protease inhibitors, new inhibitorssuch as Compound 1 (molar mass: 483.5 g.mol-¹) are being tested.Compound 1Compound 1 has been shown to inhibit HIV-1 protease with K₁ = 60.3μM (Table 1). K; is the dissociation constant for the enzyme-boundinhibitor, which is either El or ESI, depending on the type of inhibitor. Thepeptide substrate for HIV-1 protease is IRKILFLDG. HIV-1 proteasehydrolyzes only the peptide bond after leucine and beforephenylalanine.Table 1 Kinetic Parameters of HIV-1 Protease with and withoutCompound 1Compound 1(μM)K₁KM Kcat Км(mm) (¹) (mM-¹ s¹) (HM)00.1491.678 0.2500.832 0.126 0.151 60.30.149 60.30.430 0.064Note: HIV-1 protease follows Michaelis-Menten kinetics.060.0120HA Lineweaver-Burk plot of V.¹ versus [S]-1, both without Compound 1and with different concentrations of Compound 1, generates a set ofparallel straight lines with positive slopes.Adapted from T. Sperka, J. Pitlik, P. Bagossi, and J. Tösner, Bioorganic & Medicinal Chemistry Letters. ©2005Elsevier Inc.Question 2If only [1] is increased, then [ESI] or [El] increases. This is an example of:O A. the Bose-Einstein Principle.OB. the Heisenberg Uncertainty Principle.O c. the Le Châtelier's Principle.O D. the Pauli Exclusion Principle.-Question 3Which structural change to Compound 1 would make it more watersoluble?O A. Replacing benzene CH with N in the ringOB. Replacing C=0 with C=CH₂O c. Replacing N-N-N with CH-CH=CHOD. Replacing NH with NCH3OA. 33.5 and 15.7O B. 75 and 30.1Question 4In μM.s¹ and μM, what should the approximate values of keat/KM andK be, respectively, when [1] = 180 µM?O C. 150 and 60.3O D. 300 and 120.6Question 1What quantity of Compound 1 must be provided to prepare 100.00 mLof solution with a concentration equal to K;?OA. 48.4 mgO B. 24.2 mgO c. 5.64 mgOD. 2.92 mg

Compound 1 is an uncompetitive inhibitor as the LB (Lineweaver Burk) plot is said to have parallel…

Passage 1 (Questions 1-4) Human immunodeficiency virus 1 (HIV-1) protease inhibitors have been successful at lowering HIV-1 levels and blocking the onset of acquired immune deficiency syndrome (AIDS). However, because HIV-1 mutants are developing resistance to current protease inhibitors, new inhibitors such as Compound 1 (molar mass: 483.5 g.mol-¹) are being tested. Compound 1 Compound 1 has been shown to inhibit HIV-1 protease with K, = 60.3 μM (Table 1). K; is the dissociation constant for the enzyme-bound inhibitor, which is either El or ESI, depending on the type of inhibitor. The peptide substrate for HIV-1 protease is IRKILFLDG. HIV-1 protease hydrolyzes only the peptide bond after leucine and before phenylalanine. Compound 1 (μm) Table 1 Kinetic Parameters of HIV-1 Protease with and without Compound 1 10 60.0 120 H 00.149 0.832 0.126 0.151 60.3 0.430 0.064 0.149 60.3 Note: HIV-1 protease follows Michaelis-Menten kinetics. FN A Lineweaver-Burk plot of V.¹ versus [S]-¹, both without Compound 1 and with different concentrations of Compound 1, generates a set of parallel straight lines with positive slopes. K₁ KM Kcat KM (MM) (S¹) (mM-¹ s¹) (UM) 1.678 0.250 Adapted from T. Sperka, J. Pitlik, P. Bagossi, and J. Tösner, Bioorganic & Medicinal Chemistry Letters. ©2005 Elsevier Inc. Question 2 If only [1] is increased, then [ESI] or [El] increases. This is an example of: O A. the Bose-Einstein Principle. OB. the Heisenberg Uncertainty Principle. OC. the Le Châtelier's Principle. O D. the Pauli Exclusion Principle. Question 3 Which structural change to Compound 1 would make it more water soluble? O A. 33.5 and 15.7 O A. Replacing benzene CH with N in the ring OB. Replacing C=0 with C=CH₂ OC. Replacing N-N-N with CH-CH=CH O D. Replacing NH with NCH3 OB. 75 and 30.1 Question 4 In μM-s¹ and μM, what should the approximate values of kcat/KM and K, be, respectively, when [1] = 180 µM? O c. 150 and 60.3 O D. 300 and 120.6 Question 1 What quantity of Compound 1 must be provided to prepare 100.00 mL of solution with a concentration equal to K₁? OA. 48.4 mg OB. 24.2 mg O c. 5.64 mg OD. 2.92 mg