Only handwritten, No chatgpt B 4. The framp is loaded as shown. Determine reactions at A and B and the force on the pin at B. a=2m, b=5 m, c=3 m, d=3m, P=2 kN, M=5 kN·m.
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- 3The truss shown beiow is supported by a pin support at H and a roller support at P The positive sign for vertical reactions is up. 10 kN 20 kN 20 kN 20 kN 20 kN 20 kN 10 kN B D E 3 m H J K L M N 8 @ (4 m ) Each 1. Calculate the reactions: Hy= kN Py= kN 2. Calculate the magnitude of the force in member BC: FBC= kN in 3. Calculate the magnitude of the force in member BK: FBK= kN in 4. Calculate the magnitude of the force in member JK: FJK= kN in 5. Is member DL a zero force member?Find the horizontal and vertical reactions at the pin at B. Note that the support at D is fixed. Sign convention for the positive x and y direction applies for the answers. Diagram not to scale Answers: (a) -4 kN, 2 kN (b) 4 kN, -2 kN (c) 1.5 kN, 3 kN (d) -1.5 kN, -3 kN 3 kN B A D TTT 2 m 4 kN 2 m C 1m 2 m 5 m
- Please Show All Work & StepsProblem 2: Solve for the reactions at roller A and pin G. Solve for the force members: IJ, DJ, DE. 3kps 3kips 9' G B E Gspens @ 12'For bar shown with fixed ends A and D formulate equations to calculate reactions at the ends mentioned. Draw a diagram showing the variation of the normal forces in the bar. and calculate the reactions for the following values: L1 = 200 mm, A1 = 840 mm2 L2 = 250 mm, A2 = 1260 mm2 PB = 25.5 Kn and PC = 17.0 KN.
- Rigid arm AB is subject to a downward force F=270 lbf. It is supported by asquare shaft journal bearing at A and a cable BC.A. Draw a clear and large free-body diagram (FBD) to show all reaction components on AB. Ifany are not engaged, cross them out and add the note “N.E.” for “Not Engaged.” You do NOTneed to set up any equations or solve for any of the reactions.B. Find the unit vector for cable BC.I want clear anser for that questionIf the roller A is replaced by a pin, determine the corresponding reactions at A and then Identify the ff. (a) The bar which has the largest tensile force. What is the value? (b) The bar which has the largest compressive force. What is the value? 3m 2.7 kN 30 3m E 4.5 KN 3m 1.8 KN 30 3m Assume for all bars: A = 500 mm² and E = 200 kN/mm²
- Using the method of sections, determine the forces inmembers BG, CI, and CD. Express your answers in terms of P (e.g.FA= 0.5P)3.1 Use the concepts of moment and force equilibrium, find the reactions atpoint A (FAx and FAy) and point E (FEy).3.2 Find FBG first. Cut through BC, BG, and GF, consider the Left-Hand Side(LHS) section as a whole, find FBG by considering the Free-Body Diagram(FBD), and equilibrium of forces in the y-direction.3.3 Now find FCI and FCD. Cut through CD, CI, and HI, consider the RHSsection as a whole, find FCI by considering the FBD, and equilibrium offorces in the y-direction. Then, find FCD by taking moment at point I, andconsider the concept of moment equilibrium.The pulley at D is frictionless and the cylinder weighs 180 Ib. a. Determine the vertical reaction (Ib) of the hinge. Indicate its direction, use positive value if it is upward and negative if it's downward. b. Determine the horizontal reaction (Ib) of the hinge. Indicate its direction, use positive value if it's to the right and negative if it's to the left. c. Determine the tensile force (Ib) on the cable. A B C 5 ft 5 ft -3 ftF1 d F2 E F3 a= 2.9m, b = 2.2m, c = 4.5m, d= 1.2m F=120N, F,= 2400N, 0, = 35°, F;= 500N. For the truss as shown and the loading indicated. 1. Use the method of joints to find the forces in AB and AG. Show the free body diagram for the joint: Olncluded in manual solution ONot made The force in member AB is: N (Tension:+, Compression: -1 The force in member AG is: N [Tension:+, Compression: -) 2. Find the force in members BC, BE, EF using the method of section. Show the free body diagram with required dimensioris and inclinations: Olncluded in manual solution ONot made The force in member EF: N [Tension:+, Compression: -] The force in member BC: N [Tension:+, Compression: -) The force in member BE: N (Tension:+, Compression: -] (Answer upto 1 decimal place for all values)