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- Calculate the stiffness matrix for the Q8 element shown below. Make use of the shape functions in natural coordinates and the Jacobian calculated in previous problems. Use 2x2 Gaussian numerical integration. Use plane strain conditions (for unit thickness) with E=200E9 (MPa) and nu=0.25. I have attached my matlab code below. Please look thru it and correct it. Thanks. u=sym('u') %%ztav=sym('v') %%eta x1=1x2=2x3=3.5x4=3.6x5=4.0x6=2.3x7=1.2x8=0.8 y1=1y2=1y3=1.3y4=2.3y5=3.3y6=3.2y7=3.0y8=2.0X=[x1;x2;x3;x4;x5;x6;x7;x8]Y=[y1;y2;y3;y4;y5;y6;y7;y8]%% diff of ztaDN1Du=1/4*(1-v)*(2*u+v);DN2Du=-u*(1-v);DN3Du=1/4*(1-v)*(2*u-v);DN4Du=1/2*(1-v^2);DN5Du=1/4*(1+v)*(2*u+v);DN6Du=-u*(1+v);DN7Du=1/4*(1+v)*(2*u-v);DN8Du=-1/2*(1-v^2); %% diff of etaDN1Dv=1/4*(1-u)*(2*v+u);DN2Dv=-1/2*(1-u^2);DN3Dv=1/4*(1+u)*(2*v-u);DN4Dv=-v*(1+u);DN5Dv=1/4*(1+u)*(2*v+u);DN6Dv=1/2*(1-u^2);DN7Dv=1/4*(1-u)*(2*v+u);DN8Dv=-v*(1-u);%% find dx/du dx/dv, dy/du and dy/dva=[DN1Du, DN2Du, DN3Du, DN4Du, DN5Du, DN6Du,DN7Du,…Answered: T Blackboard @ Texas X Bb MasteringEngineering - Spring 2 × E MasteringEngineering Mastering x > (195) Find the resultant force acti X O (195) Morgan Wallen - Cover i session.masteringengineering.com/myct/itemView?assignmentProblemID=12360390 ABP G I Review Suppose that h = 4 m. (Figure 1) Part C Determine the coordinate direction angle B of the resultant force of the two forces acting on the sign at point A. Express your answer using three significant figures. B = 90 Submit Previous Answers v Correct Part D Figure 1 of 1 Determine the coordinate direction angle y of the resultant force of the two forces acting on the sign at point A. 2 m Express your answer using three significant figures. E 2 m B Hν ΑΣφ ? vec F = 350 N Fc= 400 NA F = 400 N 2 m Submit Request Answer 3 m Provide Feedback Next > 11:50 PM O Type here to search 2/7/202160% 9:54 AM BSME 2-2 STATICS OF RIGID... A drive.google.com 4. Draw the f BD C rod AB An- Cable 5. Draw the FBD @ Cylinder and rod A FB ...
- Please show the work to understand the process. AI generated steps have been wrong.Suppose a steel part is subject to to stress states: State one has a completely reversing stress amplitude of 32 ksi and state two have a completely reversing stress amplitude of 41 ksi. Further, suppose that in high cycle finite life region of the S-N diagram the relationship between stress and life is given by S = 95.1N^-0.0851 where S is in ksi and N is in Cycles. According to our methods, if this part is subjected to 29506 cycles at state one how many cycles of remaining life can we expect at state two? Answer must be in cyclesE and 5 v X O file:///C:/Users/Hp/Desktop/mm/OUTCOME%20NO.2%20and%205%20with%20Problems.pdf + O Fit to page D Page view A Read aloud 1 Add notes Problems 1. A brass rod of diameter 25 mm and length 250 mm is subjected to a tensile load of 50 kN and the extension of the rod is equal to 0.3 mm. Find the Young's Modulus or Modulus of Elasticity. 99+ to search hp delete prt sc 14 DI backs & 7 8 24 4 P EJR -0 J K H D. F
- mathlab code: %Press-Fit Example Problem 117 %Steel, psi ES=30*10^6 MuS=0.292; %Cast Iron EC=14.5*10^6; MuC=0.211; di=0; d0=2.002; Di=2.000; D0=3.000; % tolerance tol=d0-D0; % Pressure Eq. (3-56) R=Di/2; r0=D0/2; ri=di/2; Hub=(1/ES)*((r0^2+R^2)/(r0^2-R^2)+MuS); Inner=(1/EC)*((R^2+ri^2)/(R^2-ri^2)-MuC); p=tol/(R*(Hub+Inner))d) Find the time constant associated with this transient analysis. e) Find the time it takes for the temperature of the wire surface to reach a temperature that is within 2∘C of the steady-state temperature of the wire.Theory of vibration exercise
- Free Vibration Acceleration Time History 0.5 1,-0.424 sec Accel, 0.423 g 0.4 0.3 t4.958 sec Accel0.194 g 02 0.1 -0.1- -0.2 -0.3 -0.4- -0.5 Time (sec) Calculate the natural frequency of the structure from the experimental testing results shown below which were obtained from a free vibration test of the SDOF structure. Acceleration (b) For the torsion bar shown below: 3) Derive the equations as functions of the independent variable and the input variables for Mx, Øx9, Ex8, and 0 4) Plot the graphs of the above four variables in the order listed above as functions of the independent variable A=constant Right end is fixed (0(x=L)=0) G=constant T Left end is fixed (0(x=0)=0) L/2 L/2Needs Complete typed solution with 100 % accuracy