12.30m F=5.3 KN 7.2 m 9.6 m B x
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A tension force F of magnitude 5.3 kN is applied to the cable attached to the top of the rigid mast and secured to the ground.
Compute the component of F along the x-axis (kN).
Answer: A. 2.96
Compute the component of F along the y-axis (kN).
Answer: C. 3.79
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- The stress-strain diagram for a polyester resin is given in Figure 2. The rigid beam AC is supported by a strut AB and post CD, where both are made from this resin material. a) When beam AC is subjected to a load of P = 80 kN, determine the angle of tilt of the beam when the load is applied. Assume that the diameter of the strut is 40 mm and the diameter of the post is 80 mm. b) Determine the largest load P that can be applied to the beam before it ruptures. Assume that the diameter of the strut is 12 mm and the diameter of the post is 40 mm. c) Based on the value of P in (b), suggest one material that will not rupture if the applied load is 5P. Explain your answer mathematically.Q 5 A vertical axis circular cylindrical water storage tank of cross-sectional area A is filled to a depth of 15 m. The tank is 4 m in radius and is made of steel having a yield point of 240 MPa. If a safety factor of 2 is applied,determine the required tank wall thickness.. [Use ywater = 9800 N/m³] %3DThe state of stress at a point under plane stress condition is Ox = 100 MPa, Oy = 50 MPa, Txy = 20 MPa %3D The radius of the Mohr's circle representing the given state of stress in MPa is: O 32.02 O5071 O60 23 O 100.92
- 6) Liquid in a closed container with ₁-1000 cm³ is under pressure p₁-1×10 N/m². Volume of the liquid is reduced to V₂=995 cm' when pressure increased to p=2×10 N/m². Calculate volumetric elasticity modulus of the liquid.2. Calculate the heat loss for the structure described below. Use the indoor design setpoint of 70°F. ● . . . ● ● Hint: Utilize the Q=U*A*(ti-to) & Q = U'*P*(ti-to). Make sure to reference the following tables and examples to help assist you solve this problem; Table 5-5a, Table 5-8, Table 5-4a, Example 5-3, Eq. 5-23, and Fig 5-8. Given: i. Location: Des Moines, IA @ 99% winter OAT ii. Walls: Table 5.7, Construction 2 iii. Floor: Concrete slab with 2-ft, R-5.4, vertical edge insulation iv. Windows: Double-Insulating Glass; 1/4-in. air space; e = 0.6 on surface 2, 3x4-ft, double hung, reinforced vinyl frame; three on each side v. vi. Roof-Ceiling: Same as Example 5.3, height of 8-ft vii. House Plan: Single story, 36-ft x 64-ft Doors: Wood, 1-3/4-in. panel doors with metal storm doors, three each, 3x6.75-ft Qwindows = Qdoors= Qwalls = Qroof/ceiling= Qfloor = QTOTAL = Btu/(hroft²0F) Btu/h Heat Loss Btu/h Heat Loss Btu/h Heat Loss Btu/h Heat Loss Btu/h Heat LossFind the force pneed to fill the gap. Young's modulus as 300 GPa C 1,5 cm² 2 cm2 P. A 1 cm 1/2 p 0.5 m 0.5 m 1 m 0.5 mm (a) 13.84KN. (b) 14.21KN.
- The Airy stress function for a cantilever beam loaded by a force applied at the opposite side to the built-in end is given by p=Axy 3 where the x coordinate runs along the length of the beam, the y coordinate runs along the width of the beam and A is an arbitrary constant which can be determined through application of boundary conditions. Which equation gives the shear stresses, ? O 0 O 6Axy O-3Ay² O-6AxyDetermine the displacements of nodes of the spring system shown in Fig. Pl.12. 40 Nimm 60 N. 50 N www 80 N/mm số N/mm FIGURE P1.12Determine the reaction forces at B and C. 18.0 kN/m A OR CO Cy -210m -3.75 m 2.75m D. -61.3 -7.72 1. reaction force at B= kN 7.72 2. reaction force C kN -54.46 3. reaction force C - kN 76.0 Not an answer +61.3 +6.86
- The shaded region represents a thin piece of metal.Use integration to determine the coordinates of the centroid of this thinmetal piece.4.1 Use double integration, set your dA = dxdy4.2 Use single integration, add up the infinitesimally small, vertical ‘slices’4.3 Use single integration, add up the infinitesimally small, horizontal‘slices’.A bar with varying cross section is subjected to various forces as shown below. Compute: a) Stresses in each section b) strain in each section c) total extension of the bar. Take E = 2.1x105 N/mm² 400 mm² P1=10kN A 1000 mm B 800 mm mm² P₂ P3=45KN+ 1500 mm 600 mm² 800 mm → P4-35kNSolve both the parts.