20 cm dia A 100 - 0.5Z cm T₁ Τι 100 - 0.5Z cm 3+ (Z/20)KN 2 kN 100 0.5Z cm
The figure below shows a countershaft (20 cm diameter) with 2 V-belt pulleys with all elements
separated equidistant at a spacing of 100 – 0.5Z cm. A motor powers pulley C (200 cm diameter)
through a belt, with the tension at the tighter side being 3 + (Z/20) kN while the loose side is 2 kN.
The power is transmitted through the shaft and delivered to the belt on pulley B (100 cm diameter).
For pulley B, assume that the belt tension on the loose side at B is 30 percent of the tension on the
tight side. Assume the shaft runs at a constant speed and the bearings act as simple supports. Z is 50.
a) Determine the unknown tensions in the belt on pulley B.
b) Find the reaction forces at the bearings.
c) Draw shear force and bending moment diagrams on the x-y plane.
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