Calculate the percent cold reduction when platinum wire is cold-drawn from a diameter of 5.53 mm to a diameter of 3.35 mm.
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Calculate the percent cold reduction when platinum wire is cold-drawn from a diameter of 5.53 mm to a diameter of 3.35 mm.
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- Calculate the percent cold reduction when ansteel wire is cold drawn from a diameter of 6 mm to a diameter of 3 mm.Don't Copy . 4. Calculate the percent cold reduction when an Al wire is cold drawn from a diameter of 5 mm to a diameter of 2 mm.Aluminium and copper wires can not be made by cold drawing process. Select one: True False
- Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equation 6.5 for elastic deformation, that the modulus of elasticity is 172 GPa (25 × 106 psi), and that elastic deformation terminates at a strain of 0.008. For plastic deformation, assume that the relationship between stress and strain is described by Equation 6.19, in which the values for K and n are 6900 MPa (1 × 106 psi) and 0.25, respectively. Furthermore, plastic deformation occurs between strain values of 0.008 and 0.61, at which point fracture occurs. J/m³1. List at least 5 types of forming operations that are used to shape metals into functional shapes. List the names and use one short sentence to describe each of them. 2. Calculate the percent cold reduction when an Al wire is cold drawn from a diameter of 4 mm to a diameter of 2 mm. 3. Name the three basic bonding types in engineering materials, and give explanation.b) A metal wire is cold drawn from a radius of 5.75 mm to a radius of 3.25 mm. Compute the percent of the cold reduction in this process. (Ans: 68.05% c) A certain metal has a modulus of elasticity of 115 GPa, and its plastic deformation begins at a stress of 275 MPa. Calculate the maximum elongation to which it can be stretched without plastic deformation, if the metal has a length of 120 mm.
- 13.13 Tungsten is being used at half its melting point (Tm 3,400 °C) and a stress level of 160 MPa. An engineer suggests increasing the grain size by a factor of 4 as an effective means of reducing the creep rate. (a) Do you agree with the engineer? Why? What if the stress level were equal to 1.6 MPa? (b) What is the predicted increase in length of the specimen after 10,000 hours if the initial length is 10 cm? (Hint: Use a Weertman--Ashby map.) 1) Where in the book/slides is this covered? = page # or slide session/number 2) What equations and concepts apply here? Normalized tensile stress, o/G 10-² 10-4 10-6 10-8 0 Tungsten d = 10um, p = 4x 1010/cm² Theoretical strength Dislocation glide Coble creep 0.2 10-10 0.4 Dislocation creep /s 10-6 0.6 0.8 Homologous temperature, T/TM 10-2 10-4 10-6 Nabarro creep ≈ 1.0 ၆ SS Dislocation creep mechanism Dislocation glide climb, climb controlled Dislocation glide climb, glide controlled Dissolution of dislocation loops Dislocation climb without…Please solveDescribe the conditions that favor cutting of a particle vs. looping of a dislocation around a particle.
- Illustrate and briefly describe the typical creep curve for a metal.Note: Answer Should be not so long. Need straight forward Answer. By considering a circular hole in a thin elastic sheet, explain (with the aid of any diagrams as appropriate) how a stress concentration can magnify stress. Also Explain the principles of designing alloys for oxidation resistance.A wing component on an aircraft is fabricated from an aluminum alloy that has a plane strain fracture toughness of 28 . It has been determined that fracture results at a stress of 106 when the maximum internal crack length is 9.2 . For this same component and alloy, compute the stress level at which fracture will occur for a critical internal crack length of 6.6 .