Determine equivalent inertia and equivalent stiffness of the system shown in Figure. Mass of the bar is M. Use rotation of the bar (0) as the generalized coordinate. L L/4 2m k₁ m 2k
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- Determine equivalent inertia and equivalent stiffness of the system shown in Figure. Mass of the bar is M. Use rotation of the bar (0) as the generalized coordinate. L L/4 2m k₁ m 2kUse the given values in problem to answer the following: Find the moment of inertia and radius of gyration of the section of this bar about an axis parallel to x-axis going through the center of gravity of the bar. The bar is symmetrical about the axis parallel to y-axis and going through the center of gravity of the bar and about the axis parallel to z-axis and going through the center of gravity of the bar. The dimensions of the section are: l=51 mm, h=29 mm The triangle: hT=15 mm, lT=18 mm and the 2 circles: diameter=7.4 mm, hC=8 mm, dC=7 mm. A is the origin of the referential axis. Provide an organized table and explain all your steps to find the moment of inertia and radius of gyration about an axis parallel to x-axis and going through the center of gravity of the bar. Does the radius of gyration make sense? In the box below enter the y position of the center of gravity of the bar in mm with one decimal.Match the most appropriate form of the equation for the moment of inertia to the image shown. All objects are rotating about point O. Note: ris distance, m is a mass, k is a radius of gyration and d is a distance from the mass moment of inertia IG about the center of mass A. D. O M X Mass element Z Rotation axis X A.1=1+md² G B. = SM √² r²dm C.I=mk²_ D.1= Σm,r?
- Find the equivalent moment of inertia of the rocker arm assembly with respect to the location of kt. mass1=10kg Jo=20kg-m2 mass2=15kg, a is half of b. The rocker is 30 centimeters long. (kg-m2)5. Calculate the moments of inertia I1, I2, and I3 for a homogeneous cone of mass M whose height is h and whose base has a radius R. Choose the origin at the apex of the cone, and calculate the elements of the inertia tensor. Then make a transformation such that the center of mass of the cone becomes the origin, and find the principal moments of inertia.The figure below shows the positions of the Centers of mass of the three disks on a rotating shaft. m. =6 kg, M2=4 kg, m3=5 kg, r-=100 mm, r2=200 ver3 = 300. B to dynamically balance the shaft it is desirable to place balancing masses of 3 kg each in their planes. Balancing find the positions of the center of mass (004) of mass A in the unit of cm and degrees. The D value in the figure is 200 mm. mlg my m1 37 53 200 mm 150mm 200 mm ma Please choose one n
- Find the equivalent moment of inertia of the rocker arm assembly with respect to the location of kt mass1=5kg Jo=20kg-m2 mass2=2kg, a is half of b. The rocker is 3 meters long. (kg-m2) *Please show a detailed solution for the computation of moment of inertia.The figure below shows the positions of the Centers of mass of the three disks on a rotating shaft. m1 =8 kg, m2=2 kg, m3=5 kg, r1=70 mm, r2=50 r3 = 110.B to dynamically balance the shaft balancing masses of 6 kg each are placed in their planes. A find the positions of the center of mass (ra, ra) of its mass in mm and degrees. The D value in the figure will be taken as 330 mm. Note: moment equations can be written according to the point 0 shown in the figure. B ma m2 60 40 320 mm 230 mm 350 mm t 50 mi Please select one: A.(17,068; OA=257, 270)
- A square panel with a mass of 12 kg is suspended from point C by two ropes at points A and B. If the rope at B is suddenly cut, calculate the tension I in rope A immediately after the cut. The moment of inertia with respect to the center of mass is I = {mb². C 45° 45 A B b b (Ctrl)wheel with a mass of 20 kg and a radius of inertia of 300mm, moves under the influence of a torque of 100Nm. Find the angular acceleration of the wheel, the linear acceleration of its center O, the wheel pressure n the ground N, and the mass moment of inertia J. Give the result to 2 decimal places.4. Determine the moment of inertia and the radius of Gyration about the axis of rotation for the wheel shown in the figure below. The density of the material can be taken as 7000kg/m³ 100mm 25 mm 50 mm Dia 250mm 300mm Dia Dia