3 kN 0.8 m 4 kN 0.8 m 2 kN 0.8 m 2 kN Ο 0.4 m 1 kN 5 kN 3 kN 0.4 m 0.4 m 3 kN

I am unsure of how to solve these and if my solution is correct.

Based on the diagram, determine the magnitude of resultant vector in the cartesian form.

6 kN 45° 5 kN D C B A 3 45° 6 kN 5 kN 10 KN 0.75 m 1.50 m 1 m

400 N 3 m A, 8 m 4 m D 1200 N

) Determine the following: X of the shaded area shown in the Figure below. The weight W of the shaded area (plate), if the plate has a thickness of 5 mm and the density of the material of the plate is 7800 kg/m³ 139 mm 30⁰ 240 mm 139 mm 139 mm R-50 mm R-45 mm 25 mm X 25 mm

How do you solve for the resultant forces?

1S kN 20 kN 2 m 2 m 2 m 2 m

5 m B 4m A F = 400 N 4 m 6m

Q/ Compute the magnitude F of the force which the earth exerts on the moon, Perform the calculation in Newtons. Hint: Please use : F = G mim2 G= 6.673*10" m'/kg.s m-5.976*104 kg mzm-6.673*10" kg r-384398*10