00(UT = Oh) = 24110.54841sec +8640184.812866sec To + 0.093104 T² -0.0000062 - T . JDo - 2451545 To T1 36525 JD-2451545 36525 (63) (64) where JD and JDo are the Julian date of the time of observation and the Julian Date of Oh on the date of observation.

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter5: Analysis Of Convection Heat Transfer
Section: Chapter Questions
Problem 5.2P: 5.2 Evaluate the Prandtl number from the following data: , .
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Can you solve the sidereal time equation for me? Where do you find JD and JD0 and what is the difference between the two?

00(UT = Oh) =
24110.54841sec +8640184.812866sec To + 0.093104 T² -0.0000062 - T
.
JDo - 2451545
To
T1
36525
JD-2451545
36525
(63)
(64)
where JD and JDo are the Julian date of the time of observation and the Julian Date
of Oh on the date of observation.
Transcribed Image Text:00(UT = Oh) = 24110.54841sec +8640184.812866sec To + 0.093104 T² -0.0000062 - T . JDo - 2451545 To T1 36525 JD-2451545 36525 (63) (64) where JD and JDo are the Julian date of the time of observation and the Julian Date of Oh on the date of observation.
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