Please solve the question Examples 7A particle moves in a straight line with a constant acceleration of -4 ft/s2 for 6 s, zeroacceleration for the next 4 s, and a constant acceleration of +4 ft/s2 for the next 4 s. Knowingthat the particle starts from the origin and that its velocity is -8 ft/s during the zero-accelerationtime interval, (a) construct the v - t and x - t curves for 0 sts 14 s, (b) determine the positionand the velocity of the particle and the total distance traveled when t = 14 s.a (ft/s²)40-461014t(s)

Step 1: Construct the velocity versus time curve We can see from the given acceleration versus time…

Answered: Examples 7 A particle moves in a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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At t = 0 a truck starts from rest at x = 0 and speeds up in thepositive x-direction on a straight road with acceleration aT. At the sametime, t = 0, a car is at x = 0 and traveling in the positive x-direction withspeed vC. The car has a constant negative x-acceleration: acarx = -aC,where aC is a positive quantity. (a) At what time does the truck pass thecar? (b) At what x-coordinate does the truck pass the car?
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Q No 1: The position of a particle moving along the x-axis is given by x=A+B t3, where A=9.75 cm and B=1.50cm/s3.consider the time interval t=2 to t=3s and calculate (a).the average velocity; (b).the instantaneous velocity at t=2s;(c). the instantaneous velocity at t=3s;(d). the instantaneous velocity at t=2.5s;(e). the instantaneous velocity when the particle is midway between its positions at t=2s and t=3s.
A turtle crawls along a straight line, which we’llcall the x-axis with the positive direction to the right. The equationfor the turtle’s position as a function of time is x 1t2 = 50.0 cm +(2.00 cm/s)t - (0.0625 cm/s2)t2. Sketch graphs of x versus t, vx versus t, and ax versus t, for the time interval t = 0 to t = 40 s.
The velocity V of a particle moving in the xy plane is given by V = (5.5t - 4.2t2) i + 8.7 j, with V in meters per second and t (> 0) in seconds. At t = 1.9 s and in unit- vector notation, what are (a) the x component and (b) the y component of the acceleration? (c) When (if ever) is the acceleration zero? (d) At what positive time does the speed equal 10 m/s?
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A police car is traveling at a velocity of 20.0 m/s due north, when a car zooms by at a constant velocity of 47.0 m/s due north. After a reaction time 0.800 s the policeman begins to pursue the speeder with an acceleration of 3.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder? Number i Units Vos A VOS North AVP AVOP AVOP Police car catches up with speeder ↑ ap Police car begins to accelerate - Speeder passes police car
Initially (at t=0 s) a weather balloon is at x = 0 and at time t (seconds) its horizontal velocity component is 0,2t m/s. The equation of its path is y = 0,2x² m. (a) Calculate the magnitude and direction of its velocity at time t = 10 s. (b) Calculate the radius of curvature at x = 10 m as well as the magnitude of the normal directed acceleration component an there. (c) Assume the acceleration a = 2,4 m/s² and the magnitude of the normal component an 0,4 m/s². Calculate the tangential component at.
i need and detailed answer to a-d thankyou^^
The figure below (not to scale) shows an acceleration-time graph of a body. a (m/s^2) 0 7 t(s) B 27 If the initial velocity was zero, a(0) = a0 = 10.7 m/s^2, a(7) = a7 = -2.2 m/s^2 and the particle's acceleration returns to zero at t = 10s, what will the body's velocity be at t = 10 s? Express your answer to three significant figures in units of m/s (but do not write the units with your answer).
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