x² + xy + y² = 1
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- The second moments of area about z-axis, /z, and the second moments of area about y-axis, ly, can be calculated as Select one: O 1. I = Iz ○ 2. Ly ○ 3. ○ 4. ○ 5. = = Iz = *D' 64 I₁ = D, Iz Ly Ly = 32 *D' = = 3 Iz = *D' 32 = *D' O 6. Iy=D, Ly = D², Iz = 32 O 7. Ly = Iz D = 64 322.) please help with problem in photo(x-5)² + y² = 25
- Referring to the figure, calculate for the following:a) Component of the 800 N force in the x-direction.b) Component of the 400 N force in the y-direction.c) Component of the 450 N force in the direction of the line of action of the 800 N force.Hello, can you please solve for angle x and alpha (a). The solution is angle x = 17.62 degrees and angle alpha = 84.9 degrees but I don't understand how to get these values. Thank you.-10.4 cm 5.4 cm 2.7 cm k3 cm cm -5 cm→ 3 сm 2 cm 2 cm THE FIGURE IS NOT DRAWN TO SCALE. The area shown is a (blue) solid trapezoid with two (white) cutouts (holes), one rectangular and one semicircular.
- In the four-rod mechanism. You have a closed polygon, where: a = length of input crank = 1 inch b = length of connecting rod = 2 inches c = length of output crank = 2 inches d = length of fixed rod = 2 inches. By varying the angle θ, the perimeter of the polygon is preserved, but not its area. Determine the angle θ where its maximum area is reached and the minimum area of the polygon.3m Find the rectangular representation of the force F, given that its magnitude 240 N. * F = -135.76 i+ 169.71 j– 101.82 k F = 135.76 i + 169.71 j+ 101.82 k F = 135.76 i - 169.71 j+ 101.82 k F = -135.76i+ 169.71 j+ 101.82 kmoment is clockwise about the x-axis. (Rest of the info for Question_2 Info.PNG) Please look at the images for details about the question.