Determine the kinetic energy and potential energy of the system of Figure. Use x1 and x2 as generalized coordinate. 2k ㅏ m 2r 2m Ip X2
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- m 3m F = 500 N Find the scalar values in each coordinate axis of force vector F.calculate the value of the scalar a such that x₁ = [ a -1 1 ], and x1 = [ 1 0 1 ] are orthogonal. Once you have found the value of a, normalize the vectors and check to see if they are still orthogonal.Example 15: The man shown in Figure pulls on the cord with a force of 70 lb. Represent this force acting on the support A as a Cartesian vector and determine its direction. 30ft -S t- 6 ft 12 it
- STATICS OF RIGID BODIES MOMENT OF A FORCE MOMENT OF A FORCE – SCALAR FORMULATIONMOMENT OF A FORCE – VECTOR FORMULATIONThe boom of a crane extends from its base at point O to its tip at point Q, as shown in the figure below. A three-dimensional coordinate system is given in this figure with coordinates for both points of O = (0,0,0) and Q = (-2, 10, 10) ft. A force with a magnitude of 10.5 kip is applied at the tip of the boom by a cable that extends from point Q to point P in the x-y plane, which has coordinates P = (9,6, 0) ft. Determine the following quantities: (a) The force Fas a Cartesian vector. F = number (rtol=0J ZA O Ур i+ number (rtol=0. (b) The moment Mo due to force Fabout point O. Mo= number (rtol=0, kip - ft (c) The magnitude of moment Mo Mo- i+ number (rtol=0/ number (rtol-0.01, atol=1e-05) ☺ j+ O j+ number (rtol=0, kip-ft o number (rtol=0. ek kip ℗ kThe moment of the force F=120 lb about the point O in Cartesian vector form is. F= 120 lb 1 ft 4 ft 2 ft 4 ft Select one: O a. Mo = 200j – 400k O b. Mo = -2007 + 400k O c. Mo = -2007j – 400k O d. Mo = 200j + 400k EN
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