Initially (at t=0 s) a weather balloon is at x = 0 and at time t (seconds) its horizontal velocity component is 0,2t m/s. The equation of its path is y = 0,2x² m. (a) Calculate the magnitude and direction of its velocity at time t = 10 s. (b) Calculate the radius of curvature at x = 10 m as well as the magnitude of the normal directed acceleration component an there. (c) Assume the acceleration a = 2,4 m/s² and the magnitude of the normal component an 0,4 m/s². Calculate the tangential component at.

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Initially (at t=0 s) a weather balloon is at x =
0 and at time t (seconds) its horizontal velocity
component is 0,2t m/s. The equation of its
path is y = 0,2x² m.
(a) Calculate the magnitude and direction of its
velocity at time t = 10 s.
(b) Calculate the radius of curvature at x = 10 m
as well as the magnitude of the normal directed
acceleration component an there.
(c) Assume the acceleration a = 2,4 m/s² and
the magnitude of the normal component an
0,4 m/s². Calculate the tangential component at.
Transcribed Image Text:Initially (at t=0 s) a weather balloon is at x = 0 and at time t (seconds) its horizontal velocity component is 0,2t m/s. The equation of its path is y = 0,2x² m. (a) Calculate the magnitude and direction of its velocity at time t = 10 s. (b) Calculate the radius of curvature at x = 10 m as well as the magnitude of the normal directed acceleration component an there. (c) Assume the acceleration a = 2,4 m/s² and the magnitude of the normal component an 0,4 m/s². Calculate the tangential component at.
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