A beam subjected to a bending moment undergo a normal stress. A study was done and a sample was obtained with the following statistical parameters: Mean stress value = 452 MPa Value of the standard distribution = 21.4 MPa. The beam is made of steel with: Mean value of yield strength = 540 MPa Value of the standard distribution of yield strength = 38.4 MPa. If the strength and stress have normal distributions, determine the reliability in % considering yielding.

In a tensile test of stainless steel, the following data were obtained: Load (N) 7,200 11,250 13.500 16,200 18.900 Elongation (mm) 0.0 0.505 2.03 5.08 20,200 15.24 20,700 13,200 24.90 10.16 21.80 The dimensions of the cylindrical specimen were initial length L₁ = 50.8 mm and initial arca A₁ - 35.8 mm² and the area at fracture was Ar 10.0 mm². Plot the stress-strain diagram and determine the following: a) Modulus of elasticity b) The yield strength at a strain offset of 0.002 c) Ultimate strength d) Fracture strength

The creep data have been taken on an ahuminum alloy at 400°C and constant stress of 25MPA are shown in below Table, Find the steady state or minimum creep rate. Time (min) strain Time (min) 16 strain 0.135 0.0 0.0 2 0.025 18 0.153 4 0.043 0.065 20 0.172 0.193 0.218 22 0.078 24 10 0.092 26 0.255 12 0.109 28 0.307 14 0.120 30 0.368

a. Plot the stress strain diagram b. Find the modulus of elasticity, ultimate stress and fracture stress and explain each term. Define modulus of toughness and find the same for the above specimen. Load (kN) Elongation (mm) 11.1 31.9 0.0175 0.0600 37.8 0.1020 40.9 0.1650 43.6 53.4 62.3 64.5 0.2490 1.0160 3.0480 6.3500

Determine the tensile yield strength (0.2% offset) and the maximum strength of a metal alloy having the following tensile stress-strain diagram. 600 500 400 500 300 400 300E 200 3200 100 100E 0.000 0.002 0.004 0.006 Strain ol 0.00 0.16 0.20 0.08 Strain 0.04 0.12 Select one: O The tensile yield strength Sy = 290 Mpa and the maximum strength Smax = 500 Mpa. O The tensile yield strength Sy = 170 Mpa and the maximum strength Smax = 400 Mca. G The tensile yield strength Sy = 200 Mpa and the maximum strength Smax = 500 Moa. O Tne tensile yield strength Sy = 390 Mpa and the maximum strength Smax= 500 Mpa. The tensile yed strength Sy = 150 Mpa and the maximum strength Smax = 250 Mpa. Stress (MPa) Stress (MPa)

Please explain all, thank you

You have been given the following set of data from a soil-geotextile friction test:   Normal stress (kPa) Peak shear strength (kPa) Residual shear strength (kPa) 17 20.2 13 35 31 22 70 52 39.5 140 94 74.5   (a) Plot the Mohr-Coulomb failure envelope (x-axis=normal stress; y-axis=shear stress) (b) Determine the peak friction angle,  and the residual friction angle, . (c) Determine the peak adhesion and the residual adhesion. (d) Calculate the fabric efficiency based on a soil friction angle of  = 35-degrees using the peak friction angle.   **HINT: the equation for efficiency of soil friction angle mobilization is:

A circular rod of hot-rolled 4340 steel (4340-HR steel – 4mm diameter, 1.35m long) is subjected to a tensile load (applied normal to the circular cross-section). The modulus of elasticity of steel is 207 GPa. What is the maximum load that can be applied without causing permanent deformation? Ultimate Yield Strength, S. Strength, S, ksi MPa ksi MPa Material 6. 41 110 124 16 3003-A 6061-A 6061-T6 Aluminum 18 8. 55 alloys 45 310 40 276 Naval brass-A 54 376 17 117 Copper alloys Cartridge brass-CR 76 524 63 434 66 455 42 290 1020-HR 1045-HR 4340-HR Steel alloys 92 638 60 414 151 1041 132 910 87 600 35 241 Stainless steels 303-A 316-A 440C-A 84 579 42 290 110 759 70 483 Titanium Commercial 80 551 70 482 Table 5.3 alloy *The numerical values given are representative, and values for specific materials could vary with composition and processing. A = annealed, HR = hot-rolled, CR = cold-rolled, and T = tempered. Ultimate and Yield %3D Strengths of Selected Metals*

. Data was collected from the tensile test demonstration for Aluminum 6061-T6. Below are the resulting stress-strain diagrams based on the tensile test we performed. o (MPa) Al 6061-T6 Stress-Strain Curve o (MPa) 350 320 300 250 200 150 100 50 0 Estimate 0 0.05 0.1 0.15 ε (mm/mm) 300 270 250 220 200 150 140 100 a) The modulus of Elasticity, E b) The yield stress, d, using the 0.2% offset method c) The strain at failure, & failure d) The modulus of resilience (approximately!) 50 0 0 Al6061-T6 Stress-Strain Curve, Magnified N 0.0032 0.002 0.004 0.006 0.008 € (mm/mm) The right diagram shows the magnified elastic region of stress-strain diagram to enhance the details.

Please answer the question clearly, stating how you chose the formulas and what each variable represents. Thank you!