Question 5 Briefly describe how a medium-carbon steel may be processed to achieve each of the following microstructures: (a) Ferrite and pearlite (b) Martensite (c) Tempered martensite (d) Bainite (e) Spheroidite
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- Use the TTT diagram for O1 Tool steel provided above to estimate the amounts ofpearlite and martensite formed in the quenched heat-treated samples.What is the composition (wt% C) of a steel with AISI designation 1090? .Would this be considered a low, medium, or high carbon steel? (circle one)Question-6 A 0.25% C hypoeutectoid plain-carbon steel is slowly cooled from 950°C to a temperature just slightly below 723°C. (a) Calculate the weight percent proeutectoid ferrite in the steel. (b) Calculate the weight percent eutectoid ferrite and weight percent eutectoid cementite in the steel.
- 19th is first priority.The TTT diagram for a 1076 eutectoid steel is given: What is the heat treatment process to form 50% Coarse Pearlite + 50% Martensite. 800 A 1400 Eutectoid temperature 700 A 1200 600 1000 500 800 400 A 600 300 M(start) 200 50% 400 M + A M(50%) M(90%) 100 200 10-1 1 10 102 103 104 105 Time (s) Temperature (°C) Temperature (°F)With respect to the S-N diagram shown below, answer the following questions:(a) for Gray cast iron, what is the projected number of cycles to failure for an induced stress of 20,000 psi?(b) What is the endurance limit and associated stress for a 0.47% heat treated carbon steel? (c) What is the endurance limit for the Aluminum-copper alloy?(d) What is the endurance strength for heat treated Alloy Steel at 400,000 cycles?
- Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. 600- Bar diameter (mm) 100 80 60 40 20 0 300 0 Cooling rate at 700°C (°C/sec). -150 55 0 تنا 25 ------- 5 S 10 12.5 8 M-R L 1/2 34-R Agitated oil 15 20 ¼ ¾ Distance from quenched end. De (Jominy distance) 5,5 54 Car Bar diameter (in.) 0 25 mm. 1 in. Hardness (Rockwell C) Where (C = center, S = surface, M-R = mid-radius) 2828 292 65 60- 55- 50 45 40 35 30 25 20 15 10 0 J 10 5140 30 20 Distance from quenched end (mm) 4340 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 40 9840 4140 8640 50One problem which contains 3 parts, a , b and cPlease explain ths graph from Materials Science and EngineeringAn Introduction