Homework Help is Here – Start Your Trial Now!
Engineering
Mechanical Engineering
Examples 7 A particle moves in a straight line with a constant acceleration of -4 ft/s2 for 6 s, zero acceleration for the next 4 s, and a constant acceleration of +4 ft/s2 for the next 4 s. Knowing that the particle starts from the origin and that its velocity is -8 ft/s during the zero-acceleration time interval, (a) construct the v-t and x-t curves for 0 st s 14 s, (b) determine the position and the velocity of the particle and the total distance traveled when t = 14 s. a (ft/s²) 4 SOLUTION 6 0 10 14 t(s) -4 12 From the a- curve (a) Construct the v-1 curve: From the v-curve (b) Construct the x-1 curve 4-24 ft/s, 4, 16 ft/s --8 ft/s V₁ = V6-4 =-8-(-24) = 16 ft/s Vio=-8 ft/s 14 = 10 +42 =-8+16 = 8 ft/s = 4 32 ft, 4-8 ft As -32 ft, 4-8 ft, 4, 8 ft x=0 x4x+y=32 ft a (A/8") 4 16 ft/s ° t(s) A--24% √(ft/s) 16 8 ° x=x+4=24 ft 10 A-8 ft 1210A-16 ft 1412A-8 ft x (ft) ཟླ༥༠༡ d₁ =|32-0-32 ft d₂-|-16-32-48 ft Total Distance Traveled 4s ≤1 ≤ 12s, 12 s sr≤ 14 s d = 32 +48 +8 8-(-)-8-|- t() d = 88 ft 12

Examples 7 A particle moves in a straight line with a constant acceleration of -4 ft/s2 for 6 s, zero acceleration for the next 4 s, and a constant acceleration of +4 ft/s2 for the next 4 s. Knowing that the particle starts from the origin and that its velocity is -8 ft/s during the zero-acceleration time interval, (a) construct the v-t and x-t curves for 0 st s 14 s, (b) determine the position and the velocity of the particle and the total distance traveled when t = 14 s. a (ft/s²) 4 SOLUTION 6 0 10 14 t(s) -4 12 From the a- curve (a) Construct the v-1 curve: From the v-curve (b) Construct the x-1 curve 4-24 ft/s, 4, 16 ft/s --8 ft/s V₁ = V6-4 =-8-(-24) = 16 ft/s Vio=-8 ft/s 14 = 10 +42 =-8+16 = 8 ft/s = 4 32 ft, 4-8 ft As -32 ft, 4-8 ft, 4, 8 ft x=0 x4x+y=32 ft a (A/8") 4 16 ft/s ° t(s) A--24% √(ft/s) 16 8 ° x=x+4=24 ft 10 A-8 ft 1210A-16 ft 1412A-8 ft x (ft) ཟླ༥༠༡ d₁ =|32-0-32 ft d₂-|-16-32-48 ft Total Distance Traveled 4s ≤1 ≤ 12s, 12 s sr≤ 14 s d = 32 +48 +8 8-(-)-8-|- t() d = 88 ft 12

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
See similar textbooks
icon
Related questions
Question
100%
Please I want to understand how that example was solved according to their step, break it down step by step please for better understanding
Examples 7 A particle moves in a straight line with a constant acceleration of -4 ft/s2 for 6 s, zero acceleration for the next 4 s, and a constant acceleration of +4 ft/s2 for the next 4 s. Knowing that the particle starts from the origin and that its velocity is -8 ft/s during the zero-acceleration time interval, (a) construct the v-t and x-t curves for 0 st s 14 s, (b) determine the position and the velocity of the particle and the total distance traveled when t = 14 s. a (ft/s²) 4 SOLUTION 6 0 10 14 t(s) -4 12 From the a- curve (a) Construct the v-1 curve: From the v-curve (b) Construct the x-1 curve 4-24 ft/s, 4, 16 ft/s --8 ft/s V₁ = V6-4 =-8-(-24) = 16 ft/s Vio=-8 ft/s 14 = 10 +42 =-8+16 = 8 ft/s = 4 32 ft, 4-8 ft As -32 ft, 4-8 ft, 4, 8 ft x=0 x4x+y=32 ft a (A/8") 4 16 ft/s ° t(s) A--24% √(ft/s) 16 8 ° x=x+4=24 ft 10 A-8 ft 1210A-16 ft 1412A-8 ft x (ft) ཟླ༥༠༡ d₁ =|32-0-32 ft d₂-|-16-32-48 ft Total Distance Traveled 4s ≤1 ≤ 12s, 12 s sr≤ 14 s d = 32 +48 +8 8-(-)-8-|- t() d = 88 ft 12
Transcribed Image Text:Examples 7 A particle moves in a straight line with a constant acceleration of -4 ft/s2 for 6 s, zero acceleration for the next 4 s, and a constant acceleration of +4 ft/s2 for the next 4 s. Knowing that the particle starts from the origin and that its velocity is -8 ft/s during the zero-acceleration time interval, (a) construct the v-t and x-t curves for 0 st s 14 s, (b) determine the position and the velocity of the particle and the total distance traveled when t = 14 s. a (ft/s²) 4 SOLUTION 6 0 10 14 t(s) -4 12 From the a- curve (a) Construct the v-1 curve: From the v-curve (b) Construct the x-1 curve 4-24 ft/s, 4, 16 ft/s --8 ft/s V₁ = V6-4 =-8-(-24) = 16 ft/s Vio=-8 ft/s 14 = 10 +42 =-8+16 = 8 ft/s = 4 32 ft, 4-8 ft As -32 ft, 4-8 ft, 4, 8 ft x=0 x4x+y=32 ft a (A/8") 4 16 ft/s ° t(s) A--24% √(ft/s) 16 8 ° x=x+4=24 ft 10 A-8 ft 1210A-16 ft 1412A-8 ft x (ft) ཟླ༥༠༡ d₁ =|32-0-32 ft d₂-|-16-32-48 ft Total Distance Traveled 4s ≤1 ≤ 12s, 12 s sr≤ 14 s d = 32 +48 +8 8-(-)-8-|- t() d = 88 ft 12
Expert Solution
steps

Step by step

Solved in 2 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY
SEE MORE TEXTBOOKS