A genetic experiment involving peas yielded one sample of offspring consisting of 408 green peas and 154 yellow peas. Use a 0.05 significance level to test the claim that under the same​ circumstances, 27​% of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution.       What are the null and alternative​ hypotheses?   A. H0: p=0.27 H1: p>0.27   B. H0: p=0.27 H1: p≠0.27   C. H0: p=0.27 H1: p<0.27   D. H0: p≠0.27 H1: p<0.27   E. H0: p≠0.27 H1: p=0.27   F. H0: p≠0.27 H1: p>0.27 What is the test​ statistic?   z=enter your response here ​(Round to two decimal places as​ needed.) What is the​ P-value?   ​P-value=enter your response here ​(Round to four decimal places as​ needed.) What is the conclusion about the null​ hypothesis?   A. Reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α.   B. Fail to reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α.   C. Fail to reject the null hypothesis because the​ P-value is greater than the significance​ level, α.   D. Reject the null hypothesis because the​ P-value is greater than the significance​ level, α. What is the final​ conclusion?   A. There is not sufficient evidence to warrant rejection of the claim that 27​% of offspring peas will be yellow.   B. There is not sufficient evidence to support the claim that less than 27​% of offspring peas will be yellow.   C. There is sufficient evidence to warrant rejection of the claim that 27​% of offspring peas will be yellow.   D. There is sufficient evidence to support the claim that less than 27​% of offspring peas will be yellow.

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A genetic experiment involving peas yielded one sample of offspring consisting of
408
green peas and
154
yellow peas. Use a
0.05
significance level to test the claim that under the same​ circumstances,
27​%
of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution.
 
 
 
What are the null and alternative​ hypotheses?
 
A.
H0: p=0.27
H1: p>0.27
 
B.
H0: p=0.27
H1: p≠0.27
 
C.
H0: p=0.27
H1: p<0.27
 
D.
H0: p≠0.27
H1: p<0.27
 
E.
H0: p≠0.27
H1: p=0.27
 
F.
H0: p≠0.27
H1: p>0.27
What is the test​ statistic?
 
z=enter your response here
​(Round to two decimal places as​ needed.)
What is the​ P-value?
 
​P-value=enter your response here
​(Round to four decimal places as​ needed.)
What is the conclusion about the null​ hypothesis?
 
A.
Reject
the null hypothesis because the​ P-value is
less than or equal to
the significance​ level,
α.
 
B.
Fail to reject
the null hypothesis because the​ P-value is
less than or equal to
the significance​ level,
α.
 
C.
Fail to reject
the null hypothesis because the​ P-value is
greater than
the significance​ level,
α.
 
D.
Reject
the null hypothesis because the​ P-value is
greater than
the significance​ level,
α.
What is the final​ conclusion?
 
A.
There
is not
sufficient evidence to warrant rejection of the claim that
27​%
of offspring peas will be yellow.
 
B.
There
is not
sufficient evidence to support the claim that less than
27​%
of offspring peas will be yellow.
 
C.
There
is
sufficient evidence to warrant rejection of the claim that
27​%
of offspring peas will be yellow.
 
D.
There
is
sufficient evidence to support the claim that less than
27​%
of offspring peas will be yellow.
A genetic experiment involving peas yielded one sample of offspring consisting of 408 green peas and 154 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null
hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
What are the null and alternative hypotheses?
В. Но: р30.27
А. Но р3D0.27
H1:p>0.27
H1:p#0.27
С. Но р30.27
D. Ho: p+ 0.27
H1:p<0.27
H1:p<0.27
F. Hо: р#0.27
H1:p>0.27
E. Но: р#0.27
H4: p= 0.27
What is the test statistic?
z =
(Round to two decimal places as needed.)
What is the P-value?
P-value =
(Round to four decimal places as needed.)
What is the conclusion about the null hypothesis?
A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, oa.
C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
D. Reject the null hypothesis because the P-value is greater than the significance level, a.
What is the final conclusion?
A. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
B. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
C. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
D. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
O O O
Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 408 green peas and 154 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? В. Но: р30.27 А. Но р3D0.27 H1:p>0.27 H1:p#0.27 С. Но р30.27 D. Ho: p+ 0.27 H1:p<0.27 H1:p<0.27 F. Hо: р#0.27 H1:p>0.27 E. Но: р#0.27 H4: p= 0.27 What is the test statistic? z = (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, oa. C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. D. Reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? A. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. B. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. C. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. D. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. O O O
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