A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identifythe null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomialdistribution.What are the null and alternative hypotheses?O A. Ho: p0.27H₁: p<0.27O C. Ho: p0.27H₁: p= 0.27O E. Ho: p0.27H₁: p > 0.27What is the test statistic?Z=(Round to two decimal places as needed.)What is the P-value?P-value=(Round to four decimal places as needed.)What is the conclusion about the null hypothesis?A. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.C. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.D. Reject the null hypothesis because the P-value is greater than the significance level, a.What is the final conclusion?A. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.B. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.C. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.D. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.B. Ho: p=0.27H₁:p #0.27D. Ho: p = 0.27H₁:p>0.27OF. Ho: p= 0.27H₁: p<0.27

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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