A genetic experiment involving peas yielded one sample of offspring consisting of 427 green peas and 161 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? ⒸA. Ho: p=0.27 H₁: p=0.27 OC. Ho: p0.27 H₁: p=0.27 O E. Ho: p=0.27 H₁: p > 0.27 What is the test statistic? z = 0.21 (Round to two decimal places as needed.) What is the P-value? C O B. Ho: p=0.27 H₁: p<0.27 O D. Ho: p *0.27 H₁: p<0.27 OF. Ho: p# 0.27 H₁: p>0.27 P-value = 0.8352 (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. O C. Reject the null hypothesis because the P-value is less than or equal to the significance level, c. O D. Reject the null hypothesis because the P-value is greater than the significance level, c.

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What is the final conclusion?
A. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
B. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
C. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
D. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
Transcribed Image Text:What is the final conclusion? A. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. B. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. C. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. D. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
A genetic experiment involving peas yielded one sample of offspring consisting of 427 green peas and 161 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances,
27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim.
Use the P-value method and the normal distribution as an approximation to the binomial distribution.
What are the null and alternative hypotheses?
A. Ho: p=0.27
H₁: p=0.27
C. Ho: p0.27
H₁: p=0.27
O E. Ho: p= 0.27
H₁: p>0.27
What is the test statistic?
z = 0.21
(Round to two decimal places as needed.)
What is the P-value?
P-value = 0.8352
(Round to four decimal places as needed.)
B. Ho: p=0.27
H₁: p<0.27
O D. Ho: p0.27
H₁: p<0.27
O F. Ho: p0.27
H₁: p>0.27
What is the conclusion about the null hypothesis?
A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.
B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
C. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
D. Reject the null hypothesis because the P-value is greater than the significance level, a.
Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 427 green peas and 161 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? A. Ho: p=0.27 H₁: p=0.27 C. Ho: p0.27 H₁: p=0.27 O E. Ho: p= 0.27 H₁: p>0.27 What is the test statistic? z = 0.21 (Round to two decimal places as needed.) What is the P-value? P-value = 0.8352 (Round to four decimal places as needed.) B. Ho: p=0.27 H₁: p<0.27 O D. Ho: p0.27 H₁: p<0.27 O F. Ho: p0.27 H₁: p>0.27 What is the conclusion about the null hypothesis? A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. C. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. D. Reject the null hypothesis because the P-value is greater than the significance level, a.
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