**Hypothesis Testing for Survey Return Rates**In a study exploring cell phone usage and brain hemispheric dominance, an internet survey was sent to 6,986 individuals randomly chosen from an online group involved with ears. The survey received 1,330 responses. A 0.01 significance level is used to test whether the return rate is less than 20%. The P-value method and a normal distribution approximation for the binomial distribution are utilized.### Identify the Null and Alternative Hypotheses- **Option A:** - $ H_0: p \geq 0.2 $ - $ H_1: p < 0.2 $- **Option B:** - $ H_0: p \leq 0.2 $ - $ H_1: p > 0.2 $- **Option C:** - $ H_0: p = 0.2 $ - $ H_1: p \neq 0.2 $- **Option D:** - $ H_0: p = 0.2 $ - $ H_1: p < 0.2 $- **Option E:** - $ H_0: p \neq 0.2 $ - $ H_1: p = 0.2 $- **Option F:** - $ H_0: p > 0.2 $ - $ H_1: p \leq 0.2 $### Testing Procedure1. **Test Statistic Calculation:** - Enter the calculated test statistic $ z $, rounded to two decimal places.2. **Determine the P-value:** - Provide the P-value rounded to three decimal places.3. **Decision Making:** - Compare the P-value with the significance level to decide if the null hypothesis can be rejected. - Fill in the blanks regarding the significance level, the null hypothesis decision, and the evidence supporting whether the return rate is less than 20%.By completing these steps, you'll conclude whether there is sufficient statistical evidence to claim that the return rate is indeed less than 20%.

Name: **Hypothesis Testing for Survey Return Rates**In a study exploring ce
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Description: **Hypothesis Testing for Survey Return Rates**In a study exploring cell phone usage and brain hemispheric dominance, an internet survey was sent to 6,986 individuals randomly chosen from an online group involved with ears. The survey received 1,330

Here, the claim of the test is that the return rate is less than 20%. The hypotheses are given below: H0:p=0.2H1:p<0.2 The sample proportion is, p^=xn=13306986=0.19 The test statistic is, z=p^-pp1-pn=0.19-0.200.201-0.206986=-2.01The p-value is obtained by using Excel. From the output, the p-value is 0.022. Decision rule: If the P-value of the test is less than the level of significance, reject H0. Otherwise, fail to reject the null hypothesis H0. Conclusion: The level of significance is 0.01 and the P-value is 0.022. Here, P-value is greater than the level of significance. Thus, the decision is “ fail to reject the null hypothesis”. Therefore, there is no evidence to conclude that the return rate is less than 20%.

Math

Statistics

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6986 subjects randomly selected from an online group involved with ears. There were 1330 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6986 subjects randomly selected from an online group involved with ears. There were 1330 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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