In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6986 subjects randomly selected from an online group involved with ears. There were 1330 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.

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**Hypothesis Testing for Survey Return Rates**

In a study exploring cell phone usage and brain hemispheric dominance, an internet survey was sent to 6,986 individuals randomly chosen from an online group involved with ears. The survey received 1,330 responses. A 0.01 significance level is used to test whether the return rate is less than 20%. The P-value method and a normal distribution approximation for the binomial distribution are utilized.

### Identify the Null and Alternative Hypotheses

- **Option A:**
  - \( H_0: p \geq 0.2 \)
  - \( H_1: p < 0.2 \)

- **Option B:**
  - \( H_0: p \leq 0.2 \)
  - \( H_1: p > 0.2 \)

- **Option C:**
  - \( H_0: p = 0.2 \)
  - \( H_1: p \neq 0.2 \)

- **Option D:**
  - \( H_0: p = 0.2 \)
  - \( H_1: p < 0.2 \)

- **Option E:**
  - \( H_0: p \neq 0.2 \)
  - \( H_1: p = 0.2 \)

- **Option F:**
  - \( H_0: p > 0.2 \)
  - \( H_1: p \leq 0.2 \)

### Testing Procedure

1. **Test Statistic Calculation:**
   - Enter the calculated test statistic \( z \), rounded to two decimal places.

2. **Determine the P-value:**
   - Provide the P-value rounded to three decimal places.

3. **Decision Making:**
   - Compare the P-value with the significance level to decide if the null hypothesis can be rejected.
   - Fill in the blanks regarding the significance level, the null hypothesis decision, and the evidence supporting whether the return rate is less than 20%.

By completing these steps, you'll conclude whether there is sufficient statistical evidence to claim that the return rate is indeed less than 20%.
Transcribed Image Text:**Hypothesis Testing for Survey Return Rates** In a study exploring cell phone usage and brain hemispheric dominance, an internet survey was sent to 6,986 individuals randomly chosen from an online group involved with ears. The survey received 1,330 responses. A 0.01 significance level is used to test whether the return rate is less than 20%. The P-value method and a normal distribution approximation for the binomial distribution are utilized. ### Identify the Null and Alternative Hypotheses - **Option A:** - \( H_0: p \geq 0.2 \) - \( H_1: p < 0.2 \) - **Option B:** - \( H_0: p \leq 0.2 \) - \( H_1: p > 0.2 \) - **Option C:** - \( H_0: p = 0.2 \) - \( H_1: p \neq 0.2 \) - **Option D:** - \( H_0: p = 0.2 \) - \( H_1: p < 0.2 \) - **Option E:** - \( H_0: p \neq 0.2 \) - \( H_1: p = 0.2 \) - **Option F:** - \( H_0: p > 0.2 \) - \( H_1: p \leq 0.2 \) ### Testing Procedure 1. **Test Statistic Calculation:** - Enter the calculated test statistic \( z \), rounded to two decimal places. 2. **Determine the P-value:** - Provide the P-value rounded to three decimal places. 3. **Decision Making:** - Compare the P-value with the significance level to decide if the null hypothesis can be rejected. - Fill in the blanks regarding the significance level, the null hypothesis decision, and the evidence supporting whether the return rate is less than 20%. By completing these steps, you'll conclude whether there is sufficient statistical evidence to claim that the return rate is indeed less than 20%.
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