In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to6985 subjects randomly selected from an online group involved with ears. There were 1316 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to6985 subjects randomly selected from an online group involved with ears. There were 1316 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to6985 subjects randomly selected from an online group involved with ears. There were 1316 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the
![22. In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6985 subjects randomly selected from an online group involved
with ears. There were 1316 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the
normal distribution as an approximation to the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
OA. Ho:p> 0.2
H₁: p=0.2
O C. Ho: p=0.2
H₁: p<0.2
O E. Ho: P#0.2
H₁: p=0.2
The test statistic is z=
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
Because the P-value is (1).
that the return rate is less than 20%.
(2)
(1) O greater than
O less than
the significance level, (2).
reject
fail to reject
insufficient
sufficient
OB. Ho: p=0.2
H₁: p=0.2
O D. Ho: p=0.2
H₁:p> 0.2
OF. Ho: p<0.2
H₁:
p=0.2
the null hypothesis. There is (3)-
evidence to support the claim](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F717e652d-d2e5-48fc-b5bd-80fe3da265db%2F074220b9-767b-4486-9149-271d33e11025%2Fzzjzj3b_processed.png&w=3840&q=75)
Transcribed Image Text:22. In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6985 subjects randomly selected from an online group involved
with ears. There were 1316 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the
normal distribution as an approximation to the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
OA. Ho:p> 0.2
H₁: p=0.2
O C. Ho: p=0.2
H₁: p<0.2
O E. Ho: P#0.2
H₁: p=0.2
The test statistic is z=
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
Because the P-value is (1).
that the return rate is less than 20%.
(2)
(1) O greater than
O less than
the significance level, (2).
reject
fail to reject
insufficient
sufficient
OB. Ho: p=0.2
H₁: p=0.2
O D. Ho: p=0.2
H₁:p> 0.2
OF. Ho: p<0.2
H₁:
p=0.2
the null hypothesis. There is (3)-
evidence to support the claim
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