Identify the null hypothesis and alternative hypothesis.OA. Ho: p>0.2H₁: p=0.2OC. Ho: p<0.2H₁: p=0.2O E. Ho: p*0.2H₁: p-0.2The test statistic is z-(Round to two decimal places as needed.)The P-value is(Round to three decimal places as needed.)Because the P-value isthe significance level,the null hypothesis. There isOB. He: p=0.2H₁: p*0.2O D. He: p= 0.2H₁: p>0.2OF. He: p=0.2H₁: p<0.2evidence to support the claim that the return rate is less than 20%. In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6961 subjects randomly selected from an online group involved with ears. There were 1347 surveys returned. Use a 0.01 significance level to test the claim that the return rate isless than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.C

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Answered: In a study of cell phone usage and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6971 subjects randomly selected from an online group involved with ears. There were 1319 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
27. The average number of cavities that 30-year-old Americans have had in their lifetimes is 7.0. The standard deviation 2.7 cavities. Is the mean different for 20-year-olds? The data show the results of a survey of 15 twenty-year-olds who were asked how many cavities they have had. Assume that that distribution of the population is normal. 6, 7, 5, 3, 7, 8, 4, 6, 5, 6, 4, 6, 7, 6, 9 What can be concluded at the 0.05 level of significance? H0: = 7 Ha: [ Select ] ["<", ">", "Not Equal To"] 7 Test statistic: [ Select ] ["Z", "T"] p-Value = [ Select ] ["0.13", "0.26", "0.03", "0.06"] [ Select ] ["Fail to Reject Ho", "Reject Ho"] Conclusion: There is [ Select ] ["statistically…
A research team is working on a project to study the time (in seconds) for high school male runners to finish a 400-meter race. Jimmy, a junior researcher in the team, has randomly selected a sample of 25 male runners from a high school and the time (in seconds) for each of them to complete a 400-meter race was recorded. The sample mean running time was 53 seconds. It is assumed that the running time in a 400-meter race follows a normal distribution with a population standard deviation of 5.5 seconds.(a) Give a point estimate of the population mean running time for a 400-meter race.(b) Calculate the sampling error at 95% confidence level.(c) Construct a 95% confidence interval estimate of the population mean running time for a 400-meter race.
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 12people who buy insurance from Company A, the mean cost is $153 per month with a standard deviation of $16. For 15 randomly selected customers of Company B, you find that they pay a mean of $160 per month with a standard deviation of $10. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1_____μ2 Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places Step 3 of…
What’s P value =??
Small-business telephone users were surveyed 6 months after access to carriers other than Carrier A became available for wide-area telephone service. Of a random sample of 240 Carrier A users, 135 said they were attempting to learn more about their options, as did 227 of an independent random sample of 260 users of alternate carriers. Test, at the 1% significance level against a two-sided alternative, the null hypothesis that the two population proportions are the same. Click the link to view a standard normal distribution table. be the Let Px be the proportion of Carrier A users who said they were attempting to learn more about their options and Py proportion of users of alternate carriers who said they were attempting to learn more about their options. Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Px-Py=0 H₁: Px-Py 20 O D. Ho: Px-P₁ #0 H₁: Px - Py = 0 B. Ho: Px-Py = 0 H₁: Px-Py 0
In a random sample of males, it was found that 21 write with their left hands and 210 do not. In a random sample of females, it was found that 56 write with their left hands and 440 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Identify the test statistic. and p value
You read an online article that claims that 62% of 8-year-olds have social media accounts. You want to investigate that specific claim, so you set up a one-way chi square analysis and recruit 130 8-year-old participants for your sample. What is the expected frequency for the number of 8-year-olds in your sample who have social media accounts? mard Next
To evaluate if auditors might be helped in determining the chances of fraud if they carefully measure cash flow, samples of midlevel auditors from CPA firms were asked to indicate the chance of material fraud on a scale from 0 to 100 for a case. A random sample of 36 auditors used the cash-flow information. Their mean assessment was 35.51, and the sample standard deviation was 24.14. For an independent random sample of 36 auditors not using the cash-flow information, the sample mean and standard deviation were, respectively, 40.58 and 29.18. Assuming that the two population distributions are normal with equal variances, test against a two-sided alternative the null hypothesis that the population means are equal. (Use α = 0.05.) Click the icon to view a table of critical values for the Student's t-distribution. Let μx be the mean assessment for auditors who measured cash flow and μy be the mean assessment for auditors not using the cash-flow information. Determine the null and…

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