In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level totest the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.Identify the null hypothesis and alternative hypothesis.В. Но: р3D0.2А. Но: р3D0.2H1:p>0.2H1:p<0.2С. Но: р#0.2O D. Ho: p= 0.2H4:p=0.2H1: p#0.2O F. Но: р> 0.2Е. Но: р<0.2H4:p=0.2H4:p=0.2The test statistic is z =(Round to two decimal places as needed.)The P-value is(Round to three decimal places as needed.)Because the P-value isthe significance level,the null hypothesis. There isevidence to support the claim that the return rate is less than 20%.

From the given information, the claim of the problem is the return rate is less than 20%. Null…

Answered: In a study of cell phone usage and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6976subjects randomly selected from an online group involved with ears. There were 1301 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. test statistic___ pvalue___ Because the p value is______the significance level,____the null hypothesis.There is ____edivence to support the claim that the return rate is less than 20%
The manager of a computer retail store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 4.2 years and a standard deviation of 0.5 years. He then randomly selects records on 26 laptops sold in the past and finds that the mean replacement time is 3.9 years. Find the probability that 26 randomly selected laptops will have a mean replacement time of 3.9 years or less. Round your answer to four decimal places. P(M ≤ 3.9 years)=
A certain drug is used to treat asthma. In a clinical trial of the drug, 18 of 262 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. 1-PropZTest prop 0.09 О В. Но: р#0.09 Ос. Но: р30.09 O D. Ho: p<0.09
Find the expected count under the null hypothesis. 19. A sociologist was interested in determining if there was a relationship between the age of a young adult (18 to 35 years old) and the type of movie preferred. A random sample of 93 adults revealed the following data. Use a Chi-Square independence test to determine if age and type of movie preferred are independent at the 5% level of significance. 30-35 years old Totals 24-29 years old 15 18-23 years old Drama 8. 11 34 Science Fiction 12 10 8. 30 8. 12 29 Comedy Totals 29 33 31 93 Provided the assumptions of the test are satisfied, find the expected number of 24-29 year-olds who prefer comedies under the null hypothesis. a) 8 b) 11.56 c) 10.29 d) 7.34
Help A certain drug is used to treat asthma. In a clinical trial of the drug, 27 of 273 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. 1-PropZTest prop < 0.09 z = 0.513905185 p= 0.6963408589 p= 0.0989010989 n = 273 a. Is the test two-tailed, left-tailed, or right-tailed? O Two-tailed test O Left-tailed test O Right tailed test b. What is the test statistic? (Round to two decimal places as needed.) c. What is the P-value? P-value = (Round to four decimal places as needed.) d. What is the null hypothesis, and what do you conclude about it? Identify the null hypothesis. O A. Ho: D= 0.09 Click to select your answer(s). ?
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6989 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p0.2 H: p= 0.2 H4: p>0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. Question Viewer
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6972 subjects randomly selected from an online group involved with ears. There were 1343 surveys returned. Use a 0.01 significance leve test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho:p=0.2 H1: p0.2 H1:p>0.2 H1:p= 0.2 E. Ho: p= 0.2 OF. Ho: p<0.2 H1:p#0.2 H1:p=0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. greater than less than
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6990 subjects randomly selected from an online group involved with ears. There were 1347 surveys returned. Use a 0 01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal diştribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho p>02 H p=02 О В. Но р302 H p0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. Because the P-value is the significance level,
A certain drug is used to treat asthma. In a clinical trial of the drug, 26 of 276 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. 1-PropZTest prop < 0.09 z = 0.243984084 p = 0.5963784267 p = 0.0942028986 n = 276 a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Right tailed test Left-tailed test b. What is the test statistic? (Round to two decimal places as needed.) c. What is the P-value? P-value = (Round to four decimal places as needed.) d. What is the null hypothesis, and what do you conclude about it? Identify the null hypothesis. O A. Ho: p= 0.09 Click to select your answer(s). ?
A certain drug is used to treat asthma. In a clinical trial of the drug, 21 of 291 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 11% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. 1-PropZTest prop< 0.11 z = - 2.062763692 p= 0.0195675426 p=0.0721649485 n = 291 a. Is the test two-tailed, left-tailed, or right-tailed? O Right tailed test O Two-tailed test O Left-tailed test b. What is the test statistic? (Round to two decimal places as needed.) c. What is the P-value? P-value = (Round to four decimal places as needed.) d. What is the null hypothesis, and what do you conclude about it? Identify the null hypothesis. O A. Ho: p= 0.11 ? Click to select your answer(s).
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6973 subjects randomly selected from an online group involved with ears. There were 1343 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. ..... Identify the null hypothesis and alternative hypothesis. А. Но: Р0.2 ОЕ. Но: р> 0.2 OF. Ho:p=0.2 H4:p=0.2 H1:p<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.
A study is comparing the taste of instant coffee with fresh-brewed coffee. 50 individuals(random;y sampled) take part in the study. Each individual tastes both kinds of coffee, and declares which kind he or she prefers. The order in which the two kinds of coffee are given to each individual is randomized. 32 individuals in the sample prefer the fresh-brewed coffee. Use a suitable normal approximation to find a 95% confidence interval for the proportion of all individuals who would prefer fresh-brewed coffee. What is the lower limit of this confidence interval?

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