In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6997 subjects randomly selected from an online group involved with ears. There were 1340 surveys returned. Use a 0.01 significance level totest the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.Identify the null hypothesis and alternative hypothesis.O A. Ho: p<0.2H1:p= 0.2OC. Ho:p= 0.2O B. Ho: p#0.2H,:p= 0.2O D. Ho: p>0.2H,:p= 0.2O F. Ho: p=0.2H4:p#0.2H:p<0.2O E. Ho: p= 0.2H4:p>0.2The test statistic is z=.(Round to two decimal places as needed.)The P-value is.(Round to three decimal places as needed.)Because the P-value isthe significance level,V the null hypothesis. There isevidence to support the claim that the return rate is less than 20%.

Given that Sample size n=6997 Favorable cases x =1340 Sample proportion p^=x/n =1340/6997 =0.1915

Answered: Identify the null hypothesis and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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