In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6990 subjects randomly selected from an online group involved with ears. There were 1347 surveys returned. Use a 0 01 significance level to test the claim that the return rate is less than 20%. Use the P-value method anduse the normal diştribution as an approximation to the binomial distribution.Identify the null hypothesis and alternative hypothesis.O A. Ho p>02H p=02О В. Но р302H p<02O D. Ho p<0.2O C. H, p 02H1 p=02H p=0.2O E. Ho p=02H, p 02O F. Ho p=0.2H,: p>0.2The test statistic is z=(Round to two decimal places as needed.)The P-value is(Round to three decimal places as needed.)the null hypothesis. There isevidence to support the claim that the return rate is less than 20%.Because the P-value isthe significance level,

From the provided information, Sample size (n) = 6990 From which 1347 returned. Level of…

Answered: In a study of cell phone usage and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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certain drug is used to treat asthma. In a clinical trial of the drug, 18 of 266 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. Is the test two-tailed, left-tailed, or right-tailed? What is the test statistic? What is the P-value? What is the null hypothesis, and what do you conclude about it? Decide whether to reject the null hypothesis. Choose the correct answer below.
The appropriate rejection regions for the large- sample test statistic Z in a left-tailed test at the 1% significance level is Reject Ho if: Zcal > 2.33 Reject Ho if: Zcal-2.33
The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured automobile drivers were intoxicated. A random sample of 54 records of automobile driver fatalities in a certain county showed that 34 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 77% in Kit Carson County? Use ? = 0.01. Recall that in a binomial experiment with n trials, where p is the population probability of success and q = 1 − p is the population probability of failure, the standard normal approximation to the binomial distribution is appropriate if both np > 5 and nq > 5. We are given a population probability of 77%, so p = 0.77, and a sample size of n = 54 records of automobile driver fatalities. Use these values to compute np and nq rounded to two decimal places. np= 54 ( X ) =X nq= 54 (1-X) =X Because both np and nq ---Select--- are are not…
Determine the following: • Claim • Computation • Decision (Reject Ho or failed to reject Ho) • Conclusion
Suppose that the distribution of typing speed in words per minute(wpm) for experienced typists using a new type of split key board can be approximated by a normal curve with mean 60 wpm and standard deviation 15 wpm(“The Effects of Split Keyboard Geometry on Upper body Postures,”Ergonomics [2009]:104-111). What is the probability that a randomly selected typist’s speed is at most 60 wpm? What is the probability that a randomly selected typist’s speed is less than 60 wpm? What is the probability that a randomly selected typist’s speed is between 45 and 90 wpm? Suppose that two typists are independently selected. What is the probability that both their typing speeds exceed 75 wpm? Suppose that special training is to be made available to the slowest 20% of the typists. What typing speeds would qualify individuals for this training?
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6989 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p0.2 H: p= 0.2 H4: p>0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. Question Viewer
In a study of cell phone usage and brain hemispheric dominance, an Intemet survey was e-mailed to 6992 subjects randomly selected from an online group involved with ears. There were 1294 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA Ho p0.2 H1 p 0.2 O c. Ho p# 0.2 D. Ho: p 0.2 H p 0.2 H1 p 0.2 OE. Ho p 0.2 O F. Ho p 0.2 H1 p>0.2 Hy:p<0.2 The test statistic is z (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the significance level, Because the P-value is the null hypothesis. There is evidence to support the claim that the return rate is less than 20%
Which of the following statements about the False Discovery Rate (FDR) is correct? The FDR is the only method available for controlling multiple testing error in transcriptional profiling data The FDR cutoff value should be held to the same standard as the p-value cutoff when doing hypothesis testing The FDR can be interpreted as meaning “the proportion of the significant gene list one would expect to find significant by chance due to the multiple testing error” The FDR greatly simplifies analysis, allowing researchers to add many more treatment groups to their experimental designs Its best to save your signal intensity data before calculating the FDR, as the FDR calculation will change the signal values for all of your data
7q3r2 Time 9.8 3.3 4.5 2.8 14.4 2.6 6.7 8.9 3.9 4.1 2.5 2.8 0.1 1.3 6.3 10.8 7.5
A certain drug is used to treat asthma. In a clinical trial of the drug, 18 of 282 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 11% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level. What is the final conclusion? 1-PropZTest prop < 0.11 z = -2.477964522 p=0.0066067142 p=0.0638297872 A n = 282 A. There is sufficient evidence support the claim that less than 11% of treated subjects experienced headaches. OB. There is not sufficient evidence to warrant rejection of the claim that less than 11% of treated subjects experienced headaches. OC. There is not sufficient evidence support the claim that less than 11% of treated subjects experienced headaches. D. There sufficient evidence to warrant rejection of the claim that less than 11% of treated subjects experienced…
i need help finding the pooled variance , estimated standard error, and the t statistics
What’s P value =??

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