A certain drug is used to treat asthma. In a clinical trial of the drug, 23 of 263 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. O Left-tailed test OTwo-tailed test b. What is the test statistic? (Round to two decimal places as needed.) c. What is the P-value? P-value= (Round to four decimal places as needed.) d. What is the null hypothesis, and what do you conclude about it? Identify the null hypothesis. OA. H₂:p>0.09 OB. H₂: p<0.09 OC. H₂: p=0.09 O D. H₂:p #0.09 Decide whether to reject the null hypothesis. Choose the correct answer below. OA. Reject the null hypothesis because the P-value is less than or equal to the significance level, a OB. Fail to reject the null hypothesis because the P-value is greater than the significance level, OC. Reject the null hypothesis because the P-value is greater than the significance level, a OD. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a e. What is the final conclusion? OA. There is sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches. OB. There is not sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches OC. There is not sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches. OD. There is sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches 1-PropTest prop <0.09 2-0.244362694 p=0.4426070370 -0.0074524726 n=263

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Chapter1: Starting With Matlab
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A certain drug is used to treat asthma. In a clinical trial of the drug, 23 of 263 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution
as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below.
O Left-tailed test
O Two-tailed test
b. What is the test statistic?
z=
(Round to two decimal places as needed.)
c. What is the P-value?
P-value=
(Round to four decimal places as needed.)
d. What is the null hypothesis, and what do you conclude about it?
Identify the null hypothesis.
O A. Ho:p> 0.09
O B.
Ho: p<0.09
O C.
Ho: p=0.09
O D. Ho: p *0.09
Decide whether to reject the null hypothesis. Choose the correct answer below.
O A.
Reject the null hypothesis because the P-value is less than or equal to the significance level, c.
O B.
Fail to reject the null hypothesis because the P-value is greater than the significance level, c.
O C. Reject the null hypothesis because the P-value is greater than the significance level, a.
O D. Fail
reject the null hypothesis because the P-value is less than or equal to the significance level, c.
e. What is the final conclusion?
O A. There is sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches.
O B. There is not sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches.
O C. There is not sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches.
O D. There is sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches.
O
1-PropZTest
prop <0.09
z = -0.144362694
p=0.4426070370
p=0.0874524715
n = 263
Transcribed Image Text:A certain drug is used to treat asthma. In a clinical trial of the drug, 23 of 263 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. O Left-tailed test O Two-tailed test b. What is the test statistic? z= (Round to two decimal places as needed.) c. What is the P-value? P-value= (Round to four decimal places as needed.) d. What is the null hypothesis, and what do you conclude about it? Identify the null hypothesis. O A. Ho:p> 0.09 O B. Ho: p<0.09 O C. Ho: p=0.09 O D. Ho: p *0.09 Decide whether to reject the null hypothesis. Choose the correct answer below. O A. Reject the null hypothesis because the P-value is less than or equal to the significance level, c. O B. Fail to reject the null hypothesis because the P-value is greater than the significance level, c. O C. Reject the null hypothesis because the P-value is greater than the significance level, a. O D. Fail reject the null hypothesis because the P-value is less than or equal to the significance level, c. e. What is the final conclusion? O A. There is sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches. O B. There is not sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches. O C. There is not sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches. O D. There is sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches. O 1-PropZTest prop <0.09 z = -0.144362694 p=0.4426070370 p=0.0874524715 n = 263
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