In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6983 subjects randomly selected from an online group involved with ears. There were 1315 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p=0.2 H: p>02 O C. Ho: p=0.2 H,: p#0.2 O E. Ho: p<0.2 O B. Ho: p>0.2 H,: p=02 OD. Ho: p=0.2 H: p<02 OF. Ho: p#0.2 H:p=02 H:p=02 The test statistic is zO (Round to two decimal places as needed.) The P-value isD (Round to three decimal places as needed.) Because the P-value is V the significance level, V the null hypothesis. There is v evidence to support the claim that the return rate is less than 20%.

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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6983 subjects randomly selected from an online group involved with ears. There were 1315 surveys returned. Use a 0.01 significance level to test the claim that the return
rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
O A. Ho: p=0.2
H1: p>0.2
OC. Ho: p= 0.2
О В. Но р» 0.2
H1:p= 0.2
O D. Ho: p= 0.2
H1: p#0.2
H1:p<0.2
O E. Ho: p<0.2
OF. Ho: p#0.2
H;:p=0.2
H1:p= 0.2
The test statistic is z =
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
Because the P-value is
the significance level,
V the null hypothesis. There is
evidence to support the claim that the return rate is less than 20%.
Transcribed Image Text:In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6983 subjects randomly selected from an online group involved with ears. There were 1315 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p=0.2 H1: p>0.2 OC. Ho: p= 0.2 О В. Но р» 0.2 H1:p= 0.2 O D. Ho: p= 0.2 H1: p#0.2 H1:p<0.2 O E. Ho: p<0.2 OF. Ho: p#0.2 H;:p=0.2 H1:p= 0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, V the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.
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