In a newspaper's survey of 446 people, 53.1% said that we should replace passwords with biometric security, such as fingerprints. The accompanying Statdisk display results from a test of the claim that half of us say that weshould replace passwords with biometric security. Use the normal distribution as an approximation to the binomial distribution. Use the display and a 0.10 significance level to complete parts (a) through (e).Sample proportion: 0.5313901Test Statistic, z: 1.3258Critical z: + 1.6449P-value: 0.1849...a. Is the test two-tailed, left-tailed, or right-tailed?Choose the correct answer below.two-tailedO right-tailedleft-tailedb. What is the test statistic?(Round to two decimal places as needed.)c. What is the P-value?P-value =|(Round to three decimal places as needed.)d. What is the null hypothesis, and what do you conclude about it?Activate WidowsGo to Settingp to activate WIDdaNextStatcrunch4:15 PM11/29/20212)O Type here to search3.4.5.EUGH.L.0096LR%24%23

Answered: Image /qna-images/answer/aba4ad18-65ba-44aa-ad95-2065a183bf3f.jpg

Answered: securty, such as fingerprints. The…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Phyllodes tumors of the breast are rare tumors that represent less than one percent of growths in the breast. Some researchers presented characteristics of phyllodes tumors in an article. The following table provides summary statistics for the sizes, in millimeters (mm) of independent samples of benign and malignant phyllodes tumors. Suppose that these tumor sizes are normally distributed. Use the nonpooled t-test to answer the following: At the 1% significance level, do the data provide sufficient evidence to conclude that, on average, malignant phyllodes tumors are larger than benign phyllodes tumors? a. Hypotheses: H0: ___________________ Ha: __________________________ b. Compute the test statistic: c. Determine the p-value. d. Reject null? e. Step 6: Interpret your result in a sentence
A tax collector wishes to see if the mean values of the tax-exempt properties are different for two cities. The values of the tax-exempt properties for the two random samples are show. The data are given in millions of dollars. At the 0.05 level of significance, is there enough evidence to support the tax collector's claim that the means are different? CITY A : 113 22 14 8 25 23 23 30 44 11 19 7 31 19 5 2 CITY B: 82 295 12 20 11 50 68 16 5 12 81 4 15 9 2 5 What is the sample standard deviation for city A?
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This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
The accompanying data table lists the magnitudes of 50 earthquakes measured on the Richter scale. Test the claim that the population of earthquakes has a mean magnitude greater than 1.00. Use a 0.01 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and conclusion for the test. Assume this is a simple random sample Magnitude of Earthquake 0.720 0.740 0.640 0.390 0.700 2.200 1.980 0.640 1.220 0.200 1.640 1.320 2.950 0.900 1.760 1.010 1.260 0.000 0.650 1.460 1.620 1.830 0.990 1.560 0.410 1.280 0.830 1.320 0.540 1.250 0.920 1.000 0.780 0.790 1.440 1.000 2.240 2.500 1.790
Use the Excel printout to answer the following questions. t-Test: Two-Sample Assuming Equal Variances E Variable 1 Variable 2 Mean 28.671 28.215 Variance 5.061 2.225 Observations 8 7 Pooled Variance 3.752 Hypothesized Mean Difference df 13 t Stat 0.455 P(T <= t) one-tail 0.328 t Critical one-tail 1.771 P(T <= t) two-tail 0.657 t Critical two-tail 2.160 In testing for a difference between the two population means, would you conclude that the assumption of a common variance is reasonable? O Yes, the ratio of the the larger variance to the smaller variance is less than three. O Yes, the ratio of the larger variance to the smaller variance is more than three. O No, the ratio of the larger variance to the smaller variance is less than three. O No, the ratio of the larger variance to the smaller variance is more than three. O It is not possible to check that assumption with the given information. What is the observed value of the test statistic? t = What are the degrees of freedom for the…
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
The glucose readings are 95, 86, 84, 107, 101, 112,85,86. The sample mean is 94.8, it is a normal distribution wirh the standard devian is 12.5, and the mean glucose is 85. Do these data indicate that Ben has an overall average level higher than 85? Use a=0.05, what is the level of significance? Compute z value of the sample test statistic. Find p value
A real estate agent believes that the mean home price in the northern part of a county is higher than the mean price in the southern part of the county and would like to test the claim. A simple random sample of housing prices is taken from each region. The results are shown below. Mean Variance Observations Southern Northern 155.056 168.889 345.938 560.928 18 Pooled Variance 453.433 Hypothesized Mean Difference df 34 1949 t Stat P(T<=t) one-tail p= Ex: 1.234 0.030 2.441 0.060 t Critical one-tail P(T<=t) two-tail t Critical two-tail 2.728 2. Confidence Level 99% t = Ex: 1.234 n= Ex: 9 Degrees of freedom: df = Point estimate for the southern part of the county: 1 Ex: 1.234 Point estimate for the northern part of the county: 2 0耳_ 国 23 72°F
Using the R studio dataset: tsa <- read.csv("https://remiller1450.github.io/data/tsa.csv") From this dataset, take a sample of n = 10 claims. Record the mean Close Amount of this sample. Repeat this 500 times using a for-loop. What is the mean and the standard deviation of these 500 sample means. Draw a histogram (use freq = FALSE option) of these 500 sample means.
Cell Phone Lifetimes A recent study of the lifetimes of cell phones found the average is 23.8 months. The standard deviation is 5.8 months. If a company provides its 33 employees with a cell phone, find the probability that the mean lifetime of these phones will be less than 23.8 months. Assume cell phone life is a normally distributed variable, the sample is taken from a large population, and the correction factor can be ignored. Use a TI-83 Plus/TI-84 Plus calculator. Round your answer to at least four decimal places. <PX23.8)=

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