A sample of colored candies was obtained to determine the weights of different colors. The ANOVA table is shown below. It is known that the population distributions are approximately normal and the variances do not differ greatly. Use a 0.025 significance level to test the claim that the mean weight of different colored candies is the same. If the candy maker wants the different color populations to have the same mean weight, do these results suggest that the company has a problem requiring corrective action? Source: Treatment: 5 Error: Total: Ss: 0.085 0.348 0.433 DF: MS: 0.017 0.004 Test Stat, F: Critical F: P-Value: 2.7160 4.1334 0.0020 87 92 Should the null hypothesis that all the colors have the same mean weight be rejected? O A. Yes, because the P-value is less than the significance level. O B. No, because the P-value is less than the significance level. Oc. Yes, because the P-value is greater than the significance level. O D. No, because the P-value is greater than the significance level. Does the company have a problem requiring corrective action? O A. Yes, because it is not likely that the candies do not have equal mean weights. O B. No, because it is likely that the candies do not have equal mean weights. OC. No, because it is not likely that the candies do not have equal mean weights. O D. Yes, because it is likely that the candies do not have equal mean weights.

Q: 2/18 – 12/32 + 3V50

A: The solution is given below in the next step:

Q: 5(18)

A: To find5(18)

Q: 5/14+1/6

A: 514+16=15+742

Q: expand (a-b)7

A: The solution is given in the next step.

Q: 4(5+6)=

A: Given: 4(5+6)=

Q: A 2/15 B 30 V35 5 20

A: Given,  A circle with secant and tangent  We have to find the value of x

Q: 3/8+5/24

A: The given expression is 3/8 + 5/24.Simplify the given expression as follows.

Q: Expand (a −b)4

A:

Q: (n + 4)3 =

A: Given query is to expand (n+4)3

Q: 8 13

A:

Q: 9 tmes 8

A: 9 times 8 means adding 8 upto 9 times or multiply 8 by 9.

Q: 14 1

A: Given triangle is What is another side length?

Q: 3 3/4 + 2 7/28

A:

Q: 3(m – 5) + m

A: 3(m-5)+m=0 3m-15+m=0 add both side 15 we get 2m=15

Q: 35-40 Coterminal Angles? The measures of two angles in standard position are given. Determine…

A: NOTE: Refresh your page if you can't see any equations. . two angles are coterminal if the…

Q: 8 15 2 15

A: 8/15 -2/15 here simple substraction given and fraction is given  calculation is given inbelow

Q: k 24

A: First we solve the inequality. ANd for that , we divide both sides by -6 .And on dividing by…

Q: 52 10

A: We know that nCr = n!/(n-r)!r! 5C2= 5!/(5-2)!2!        = 5*4*3*2*1/(3*2*1)(2)        = 120/12…

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.