In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6988 subjects randomly selected from an online group involved with ears. There were 1292 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method an use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA. Ho:p>0.2 H₁: p=0.2 OC. Ho: p=0.2 H₁: p<0.2 OE. Ho: p<02 H₁: p=0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level. the null hypothesis. There is CID OB. Ho: p=0.2 H₂:p>0.2 OD. Ho: p=0.2 H₁: p0.2 OF. Hop#02 H₁: p=0.2 evidence to support the claim that the return rate is less than 20%.

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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6988 subjects randomly selected from an online group involved with ears. There were 1292 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and
use the normal distribution as an approximation to the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
OA H₂:p>0.2
H₁: p=0.2
OC. Ho: p=0.2
H₁: p<0.2
OE. Ho: p<0.2
H₁: p=0.2
The test statistic is z=
(Round to two decimal places as needed.)
The P-value is.
(Round to three decimal places as needed.)
Because the P-value is
the significance level,
the null hypothesis. There is
OB. Ho: p=0.2
H₁: p>0.2
OD. Ho: p=0.2
H₁: p0.2
OF. Ho:p*0.2
H₁: p=0.2
evidence to support the claim that the return rate is less than 20%.
Transcribed Image Text:In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6988 subjects randomly selected from an online group involved with ears. There were 1292 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. OA H₂:p>0.2 H₁: p=0.2 OC. Ho: p=0.2 H₁: p<0.2 OE. Ho: p<0.2 H₁: p=0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is OB. Ho: p=0.2 H₁: p>0.2 OD. Ho: p=0.2 H₁: p0.2 OF. Ho:p*0.2 H₁: p=0.2 evidence to support the claim that the return rate is less than 20%.
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