In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6984 subjects randomly selected from an online group involved with ears. There were 1300 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
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- The manufacturer of a new eye cream claims that the cream reduces the appearance of fine lines and wrinkles after just 14 days of application. To test the claim, 10 women are randomly selected to participate in a study. The number of fine lines and wrinkles that are visible around each participant’s eyes is recorded before and after the 14 days of treatment. The following table displays the results. Test the claim at the 0.05 level of significance assuming that the population distribution of the paired differences is approximately normal. Let women before the treatment be Population 1 and let women after the treatment be Population 2. Number of Fine Lines and WrinklesBefore 11 14 13 12 15 14 9 11 11 14After 10 14 11 13 13 13 8 12 10 15 Step 1 of 3 : State the n ull and alternative hypotheses for the test. Fill in the blank below. H0Ha: μd=0: μd⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯0 3) draw a conclusion and form a decision (word it like "we…In a newspaper's survey of 446 people, 53.1% said that we should replace passwords with biometric security, such as fingerprints. The accompanying Statdisk display results from a test of the claim that half of us say that we should replace passwords with biometric security. Use the normal distribution as an approximation to the binomial distribution. Use the display and a 0.10 significance level to complete parts (a) through (e). Sample proportion: 0.5313901 Test Statistic, z: 1.3258 Critical z: + 1.6449 P-value: 0.1849 ... a. Is the test two-tailed, left-tailed, or right-tailed? Choose the correct answer below. two-tailed O right-tailed left-tailed b. What is the test statistic? (Round to two decimal places as needed.) c. What is the P-value? P-value =| (Round to three decimal places as needed.) d. What is the null hypothesis, and what do you conclude about it? Activate Widows Go to Settingp to activate WIDda Next Statcrunch 4:15 PM 11/29/2021 2) O Type here to search 3. 4. 5. E U G…The manufacturer of a new eye cream claims that the cream reduces the appearance of fine lines and wrinkles after just 14 days of application. To test the claim, 10 women are randomly selected to participate in a study. The number of fine lines and wrinkles that are visible around each participant's eyes is recorded before and after the 14 days of treatment. The following table displays the results. Test the claim at the 0.02 level of significance assuming that the population distribution of the paired differences is approximately normal. Let women before the treatment be Population 1 and let women after the treatment be Population 2. Number of Fine Lines and Wrinkles Before 12 14 13 11 11 15 10 10 10 9 After 10 14 12 12 12 15 9 7 8 Copy Data Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
- In a program designed to help patients stop smoking, 181 patients were given sustained care, and 84.5% of them were no longer smoking after one month. Use a 0.05 significance level to test the claim that 79% of patients stop smoking when given sustained care. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. identify the test statistic. identify the P-value.In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6956subjects randomly selected from an online group involved with ears. There were 1290 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. A. H0: p=0.2 H1: p≠0.2 B. H0: p=0.2 H1: p<0.2 C. H0: p>0.2 H1: p=0.2 D. H0: p≠0.2 H1: p=0.2 E. H0: p=0.2 H1: p>0.2 F. H0: p<0.2 H1: p=0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is ▼ greater than less than the significance level, ▼ fail to reject reject the null hypothesis. There is ▼ insufficient…In a random sample of males, it was found that 25 write with their left hands and 217 do not. In a random sample of females, it was found that 58 write with their left hands and 450 do not. Use a .05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Identify the test statistic.z=?
- A poll of 1086 Americans showed that 47.1% of the respondents prefer to watch the news rather than read or listen to it. Use those results with a 0.01 significance level to test the claim that fewer than half of Americans prefer to watch the news rather than read or listen to it. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution.In a random sample of males, it was found that 23 write with their left hands and 225 do not. In a random sample of females, it was found that 59 write with their left hands and 470 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females.In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6973 subjects randomly selected from an online group involved with ears. There were 1343 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. ..... Identify the null hypothesis and alternative hypothesis. А. Но: Р0.2 ОЕ. Но: р> 0.2 OF. Ho:p=0.2 H4:p=0.2 H1:p<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.
- What’s P value =??Small-business telephone users were surveyed 6 months after access to carriers other than Carrier A became available for wide-area telephone service. Of a random sample of 240 Carrier A users, 135 said they were attempting to learn more about their options, as did 227 of an independent random sample of 260 users of alternate carriers. Test, at the 1% significance level against a two-sided alternative, the null hypothesis that the two population proportions are the same. Click the link to view a standard normal distribution table. be the Let Px be the proportion of Carrier A users who said they were attempting to learn more about their options and Py proportion of users of alternate carriers who said they were attempting to learn more about their options. Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Px-Py=0 H₁: Px-Py 20 O D. Ho: Px-P₁ #0 H₁: Px - Py = 0 B. Ho: Px-Py = 0 H₁: Px-Py 0To evaluate if auditors might be helped in determining the chances of fraud if they carefully measure cash flow, samples of midlevel auditors from CPA firms were asked to indicate the chance of material fraud on a scale from 0 to 100 for a case. A random sample of 36 auditors used the cash-flow information. Their mean assessment was 35.51, and the sample standard deviation was 24.14. For an independent random sample of 36 auditors not using the cash-flow information, the sample mean and standard deviation were, respectively, 40.58 and 29.18. Assuming that the two population distributions are normal with equal variances, test against a two-sided alternative the null hypothesis that the population means are equal. (Use α = 0.05.) Click the icon to view a table of critical values for the Student's t-distribution. Let μx be the mean assessment for auditors who measured cash flow and μy be the mean assessment for auditors not using the cash-flow information. Determine the null and…