A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under thesame circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion thataddresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.C. Ho: p=0.27H₁: p<0.27OE. Ho: p=0.27H₁: p>0.27What is the test statistic?z = -2.21(Round to two decimal places as needed.)What is the P-value?P-value0.0272(Round to four decimal places as needed.)What is the conclusion about the null hypothesis?D. Ho: p=0.27H₁: p 0.27OF. Ho: p 0.27OA. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.H₁: p=0.27OB. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.OC. Reject the null hypothesis because the P-value is greater than the significance level, a.OD. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.

Given:sample size n = number of green peas + number of yellow peas = 423+125n = 548number of success…

Answered: A genetic experiment involving peas…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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