A genetic experiment involving peas yielded one sample of offspring consisting of 435 green peas and 174 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O B. Ho: p=0.26 H,: p>0.26 O A. Ho: p#0.26 H,:p=0.26 OC. Ho: p#0.26 O D. Ho: p+0.26 H:p>0.26 H:p<0.26 O E. Ho: p=0.26 OF. Ho: p=0.26 H:p<0.26 H:p#0.26 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P.value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O B. Reject the null hypothesis because the P-value is greater than the significance level, a. OC. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OD. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? O A. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. O B. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. OC. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. OD. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.
A genetic experiment involving peas yielded one sample of offspring consisting of 435 green peas and 174 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O B. Ho: p=0.26 H,: p>0.26 O A. Ho: p#0.26 H,:p=0.26 OC. Ho: p#0.26 O D. Ho: p+0.26 H:p>0.26 H:p<0.26 O E. Ho: p=0.26 OF. Ho: p=0.26 H:p<0.26 H:p#0.26 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P.value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O B. Reject the null hypothesis because the P-value is greater than the significance level, a. OC. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OD. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? O A. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. O B. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. OC. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. OD. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 435 green peas and 174 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
What are the null and alternative hypotheses?
O A. Ho: p#0.26
В. Но: р30.26
H4:p= 0.26
H1:p>0.26
Ос. Но: р#0.26
O D. Ho: p#0.26
H1:p>0.26
H1: p<0.26
O E. Ho:p=0.26
O F. Ho: p= 0.26
H1: p<0.26
H4: p#0.26
What is the test statistic?
z=
(Round to two decimal places as needed.)
What is the P-value?
P-value =
(Round to four decimal places as needed.)
What is the conclusion about the null hypothesis?
O A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.
O B. Reject the null hypothesis because the P-value is greater than the significance level, a.
O C. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
What is the final conclusion?
O A. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.
O B. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.
OC. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.
O D. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.
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