In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6980 subjects randomly selected from an online group involved with ears. There were 1296 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p>0.2 H,:p= 0.2 OC. Ho: p= 0.2 H,:p<0.2 O B. Ho: p#0.2 H,:p= 0.2 O D. Ho:p= 0.2 H,:p 0.2 OF. Ho: p=0.2 O E. Ho: p<0.2 H,:p=0.2 H,:p>0.2 The test statistic is z =. (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Because the P-value is V the significance level, V the null hypothesis. There is V evidence to support the claim that the return rate is less than 20%.

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6980 subjects randomly selected from an online group involved with ears. There were 1296 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p>0.2 H,:p= 0.2 OC. Ho: p= 0.2 H,:p<0.2 O B. Ho: p#0.2 H,:p= 0.2 O D. Ho:p= 0.2 H,:p 0.2 OF. Ho: p=0.2 O E. Ho: p<0.2 H,:p=0.2 H,:p>0.2 The test statistic is z =. (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Because the P-value is V the significance level, V the null hypothesis. There is V evidence to support the claim that the return rate is less than 20%.

Name: In a study of cell phone usage and brain hemispheric dominance, an In
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6980 subjects randomly selected from an online group involved with ears. There were 1296 surveys returned. Use a0.01 significance level to test the cl

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

In a newspaper's survey of 446 people, 53.1% said that we should replace passwords with biometric security, such as fingerprints. The accompanying Statdisk display results from a test of the claim that half of us say that we should replace passwords with biometric security. Use the normal distribution as an approximation to the binomial distribution. Use the display and a 0.10 significance level to complete parts (a) through (e). Sample proportion: 0.5313901 Test Statistic, z: 1.3258 Critical z: + 1.6449 P-value: 0.1849 ... a. Is the test two-tailed, left-tailed, or right-tailed? Choose the correct answer below. two-tailed O right-tailed left-tailed b. What is the test statistic? (Round to two decimal places as needed.) c. What is the P-value? P-value =| (Round to three decimal places as needed.) d. What is the null hypothesis, and what do you conclude about it? Activate Widows Go to Settingp to activate WIDda Next Statcrunch 4:15 PM 11/29/2021 2) O Type here to search 3. 4. 5. E U G…
Consider a sample of 50 football games, where 27 of them were won by the home team. Use a 0.05 significance level to test the claim that the probability that the home team wins is greater than one-half. What is the P-Value?
Consider a sample of 55 football games, where 29 of them were won by the home team. Use a 0.10 significance level to test the claim that the probability that the home team wins is greater than one-half.
In one city male and female voters were asked about their opinion on an environmental bond issue. Is there good evidence that one's gender influences whether a person is for or against the bond issue? A contingency table summarizing the opinions by gender is provided below. Does the data provide enough evidence to show that there is an association between gender and their opinion regarding a bond issue? Test at the 2% level and round expected values to one decimal place. VOTE VOTE For Against (Observed) Against (Expected Value) For Row (Expected Value) Gender (Observed) Total Male 54 421 475 Female 91 421 512 Column 145 842 987 Total H: Hypotheses Ho: Select an answer and Select an answer are Select an answer Ha: Select an answer and Select an answer are Select an answer Original Claim: [Select an answer
When a production line is properly adjusted, it is found that 4% of the mechanical components produced are defective. Occasionally settings go out of adjustment, and more defectives are produced. A sample of 12 components is examined and the number of defectives is counted. a. What distribution applies to the number of defectives? b. What are the null hypothesis and the alternative hypothesis? c. If the level of significance is set at 1%, how many defectives can be allowed in the sample before any action is taken?
Find the expected count under the null hypothesis. 19. A sociologist was interested in determining if there was a relationship between the age of a young adult (18 to 35 years old) and the type of movie preferred. A random sample of 93 adults revealed the following data. Use a Chi-Square independence test to determine if age and type of movie preferred are independent at the 5% level of significance. 30-35 years old Totals 24-29 years old 15 18-23 years old Drama 8. 11 34 Science Fiction 12 10 8. 30 8. 12 29 Comedy Totals 29 33 31 93 Provided the assumptions of the test are satisfied, find the expected number of 24-29 year-olds who prefer comedies under the null hypothesis. a) 8 b) 11.56 c) 10.29 d) 7.34
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6989 subjects randomly selected from an online group involved with ears. There were 1308 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p0.2 H: p= 0.2 H4: p>0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. Question Viewer
A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (31.1%), Married (55.9%), Widowed (3%), Divorced (10%). The table below shows the results of a random sample of 1824 adult men from California. Test the claim that the distribution from California is as expected at the a = 0.01 significance level. a. Complete the table by filling in the expected frequencies. Round to the nearest whole number: Frequencies of Marital Status Outcome Frequency Expected Frequency Never Married 562 Married 1024 Widowed 73 Divorced 165 b. What is the correct statistical test to use? Select an answer V c. What are the null and alternative hypotheses? Ho: O Marital status and residency are dependent. O Marital status and residency are independent. O The distribution of marital status in California is not the same as it is nationally. O The distribution of marital status in California is the same as it is nationally.
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6990 subjects randomly selected from an online group involved with ears. There were 1347 surveys returned. Use a 0 01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal diştribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho p>02 H p=02 О В. Но р302 H p0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) the null hypothesis. There is evidence to support the claim that the return rate is less than 20%. Because the P-value is the significance level,
According to Pew Research Center surveys, 12% of American adults did not own a cell phone in 2012. Suppose Verizon Wireless would like to test if this percentage has recently changed. A recent random sample of 280 American adults was selected, and it was found that 29 of them did not own a cell phone. Using ? = 0.10, answer the following: a. What type of test will be used and what distribution? b. Based on this sample and using the 6 hypothesis steps, what conclusions can Verizon Wireless make about this population?
A report states that 10% of all babies born in a certain U.S. state are preterm, which has important implications for the cost of health care. If in an SRS of 400 recent births in the state 36 were preterm, what is sampling distribution of the sample proportion? approximately N(0.10, 0.0150) approximately N(40, 6) binomial with n=400 and p=.10
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6973 subjects randomly selected from an online group involved with ears. There were 1343 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. ..... Identify the null hypothesis and alternative hypothesis. А. Но: Р0.2 ОЕ. Но: р> 0.2 OF. Ho:p=0.2 H4:p=0.2 H1:p<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.