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A genetic experiment involving peas yielded one sample of offspring consisting of 425 green peas and 159 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. ..... - -- O E. Ho: p#0.25 O F. Ho: p= 0.25 H1:p<0.25 H1: p>0.25 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. O D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. What is the final conclusion? O A. There is not sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. O B. There is not sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow. OC. There is sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. O D. There is sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow.

A genetic experiment involving peas yielded one sample of offspring consisting of 425 green peas and 159 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. ..... - -- O E. Ho: p#0.25 O F. Ho: p= 0.25 H1:p<0.25 H1: p>0.25 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. O D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. What is the final conclusion? O A. There is not sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. O B. There is not sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow. OC. There is sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. O D. There is sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A genetic experiment involving peas yielded one sample of offspring consisting of 425 green peas and 159 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. O E. Ho: p+0.25 O F. Ho: p= 0.25 H1: p<0.25 H1:p>0.25 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. What is the final conclusion? A. There is not sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. B. There is not sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow. C. There is sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. O D. There is sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow.
Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 425 green peas and 159 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. O E. Ho: p+0.25 O F. Ho: p= 0.25 H1: p<0.25 H1:p>0.25 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. What is the final conclusion? A. There is not sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. B. There is not sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow. C. There is sufficient evidence to support the claim that less than 25% of offspring peas will be yellow. O D. There is sufficient evidence to warrant rejection of the claim that 25% of offspring peas will be yellow.
A genetic experiment involving peas yielded one sample of offspring consisting of 425 green peas and 159 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? О А. Но: р#0.25 В. Но р30.25 H1: p>0.25 H1: p<0.25 Ос. Но: р30.25 O D. Ho: р#0.25 H1: p#0.25 H1:p=0.25 %3D ОЕ. Но: р#0.25 OF. Ho: p=0.25 H1: p> 0.25 H1:p<0.25 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 425 green peas and 159 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? О А. Но: р#0.25 В. Но р30.25 H1: p>0.25 H1: p<0.25 Ос. Но: р30.25 O D. Ho: р#0.25 H1: p#0.25 H1:p=0.25 %3D ОЕ. Но: р#0.25 OF. Ho: p=0.25 H1: p> 0.25 H1:p<0.25 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. C. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
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