If a sample of 50 individuals was taken from a population with a standard deviation of 12 and the sample mean is 95, what is the t-statistic for a two-tailed hypothesis test at a significance level of 0.05?
Q: A random sample of 64 business students required an average of 100 minutes to complete a statistics…
A: Given that, Mean = 100 Standard deviation = 20 Sample size = 64 95% confidence level
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: The objective of this question is to test the claim that there is a significant difference between…
Q: A researcher wants to test the claim that convicted burglars spend an average of 18.7 months in…
A: Null hypothesis: µ=18.7. Alternative hypothesis: µ≠18.7. This is a two-tailed test. Here, the sample…
Q: A management consulting company offers a 3-day seminar on project management. The consultants are…
A: 1. Objective: To determine whether the observed distribution of management positions attending the…
Q: Justine is an analyst for a sleep study center in a major city. She is looking to test the claim…
A: Decision based on p-value:At level of significance α, if the p-value ≤ α, then reject the null…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Let be the group runners training for marathons be population 1 and be the individual runners…
Q: Suppose you observe 77 data points from a distribution with standard deviation 8.4, and you…
A: Given that, σ=8.4,n=77 Critical values: By using the z-table, the critical value at 92% confidence…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Sample mean (x̅1) = 42.8Sample mean (x̅2) = 40.9Sample size (n1) = 34Sample size (n2) = 41Standard…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: The objective of this question is to test the claim that there is a significant difference between…
Q: A one-sample z-test was conducted in which the sample mean was 76, the population mean was 82, the…
A:
Q: The mean number of sick days per employee taken last year by all employees of a large city was 10.6…
A: From question we can say that, Null Hypothesis: H0: u=10.6 Alternative Hypothesis Ha: u≠10.6
Q: A random sample of 150 people shows an average salary of 371 pesos per day. With a population…
A:
Q: According to a research study, American teenagers watched 14.8 hours of television per week last…
A: In a hypothesis test if the critical region is one sided, either greater than some value or less…
Q: A screening procedure was designed to measure attitudes toward minorities as managers. High scores…
A: Given The data is as follows: Male financial analysts Female financial analysts Sample size…
Q: An article in the San Jose Mercury News stated that students in the California state university…
A: We have given the following information. Hypothesized population mean = 4.5 Sample mean =5.1 Sample…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Solution
Q: The mean factory overhead per employees in goods-producing industries is currently $4.57. Suppose a…
A: We have given that Sample size n =25 Population mean=4.57 Sample mean =3.89 Sample standard…
Q: Do the data support your claim at the 1% level?
A: The summary of the statistics is, The type of test is right tailed test
Q: A chicken farmer claims that his chickens have a mean weight of 58 ounces. The farmer takes a random…
A: In this problem, we will use z-test to solve the test statistic since the population standard…
Q: A school has 1000 students. The principal of the school thinks that the average IQ of its students…
A: Given: Sample size(n)=200Sample meanx¯=108Sample standard deviation(s)=10
Q: What is the likelihood that a randomly selected student from a population of 500 has a grade point…
A:
Q: According to a research study, American teenagers watched 14.8 hours of television per week last…
A: Given a hypothesis test to check the mean amount of time american teenagers watch television per…
Q: A researcher wants to test the average time it takes to solve a puzzle. They randomly sample 50…
A: Given: Sample size n=50 Sample mean x¯=8 Sample standard deviation s=2 Significance level α=0.05
Q: A random sample of 25 people shows an average salary of 371 pesos per day. With a population…
A: Given that Sample size n =25 Sample mean =371 Population standard deviation =45
Q: The U.S. Center for Disease Control reports that in year 1900, the mean life expectancy is 48 years…
A: Solution: Given information: n1= 29000 Sample size of white population n2= 96000 Sample size of…
Q: sample of 19 account balances of a credit company showed a mean customer balance of $4,350, but the…
A:
Q: Justin is interested in buying a digital phone. He visited 14 stores at random and recorded the…
A: Solution 95% confidence interval for the mean price of this model of digital phone $302.478 to…
Q: A random sample of 110 Americans was asked how many hot dogs they eat each year. The sample mean…
A:
Q: A researcher collects 25 data points that yield a mean of 8.164 and a standard deviation (based on N…
A:
Q: When 41 people are used the Weight Watchers diet for one year, their weight losses had a standard…
A: Hypotheses:H0: σ² = 36H1: σ² ≠ 36(Note: The value 36 comes from squaring the standard deviation of…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: From the provided information,
Q: You are doing a right-tailed hypothesis test for the mean and have to approximate the standard…
A: It is given that the test is right-tailed. Level of significance is 0.01 Degrees of freedom is 39-1=…
Q: their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. What is the…
A: Given: sample size,n = 7 population mean, μ = 6.6significance level, α = 5% = 0.05
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Given data,n1=40x1=46.6σ1=4.6n2=45x2=48.8σ2=2.4Compute value of test statistic?
Q: A researcher wants to test the hypothesis that the mean weight of packages delivered by a certain…
A: given data claim : μ = 10n = 30x¯ = 9.8s = 1.5α = 0.05
Q: 80 smokers were questioned about the number of hours they sleep each day. We want to test the…
A: From the given information we conduct Z test for mean.
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Let be the group runners training for marathons be population 1 and be the individual…
Q: A sample of 100 observations has a sample mean of 500 and a sample standard deviation of 50. Conduct…
A: Introduction: Hypothesis testing is a statistical method used to make decisions about a population…
Q: The president of a university believes the entering class this year has an average ACT score…
A: Hypothesis: The null and alternative hypotheses are below: H0: μ=23H1: μ≠23 The test statistic is…
Q: According to a survey, the average American person sleeps for 8 hours per day. To test if the amount…
A: Solution: Let X be the Amount of sleep in the New York City. From the given information, x-bar = 7.4…
Q: Suppose Michigan State University's Collegiate Employment Institute found that starting salaries for…
A: Given dataSample size(n) = 100Sample mean = 51277Hypothesized mean = 50032Sample standard deviation…
Q: A random sample of 5 students IQ scores have a mean score of 107.04 and a standard deviation of…
A: Given: Let n represents the random sample of students (n=5). Let x¯ represents the sample mean score…
Q: If a sample of 40 individuals was taken from a population with a mean of 110 and a standard…
A: Introduction In this problem, we are conducting a one-tailed hypothesis test to determine if the…
Q: A statistician is conducting a hypothesis test to determine if the average lifespan of a certain…
A: To calculate the p-value, the statistician will use a Z-test. The Z-score is calculated as follows:…
A sample of 50 individuals was taken from the population.
Sample size,
Sample mean,
Population standard deviation,
level of significance,
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 8 images
- In a simple random sample of 144 households in a county in Virginia, the average number of children in these households was 3.62 children. The standard deviation from this sample was 2.40 children. A 90% confidence interval for the mean number of children in all households in this county is?The mean number of English courses taken in a two-year time period by male and female college students is believed to be about the same. An experiment is conducted and data are collected from 24 males and 26 females. The males took an average of 4.2 English courses with a standard deviation of 1.1. The females took an average of 3.9 English courses with a standard deviation of 0.7. Conduct a hypothesis test at the 4% level of significance to determine whether the means are statistically the same. Step 1: State the null and alternative hypotheses. Ho: H1 = V H.: H1 – µ2 # v test.) (So we will be performing a two-tailedA researcher claims that the amounts of acetaminophen in a certain brand of cold tablets have a mean different than the 600mg claimed by the manufacturer. Test this claim at the .01 significance level. The mean acetaminophen content for a random sample of n = 29 tablets is 597.9 mg with a standard deviation of 3.8 mg. What are the hypotheses? What is the test statistic? Is it a z or a t? Find the P-value for this test statistic. How does it compare to the significance level? On the normal curve, indicate the location of the test statistic and the p-value. (label them on the graph) Write a conclusion in statistical terms and relate it to the parameters of this problem.
- For a random sample of 47 high school seniors in the United States in 2019, the average of typical sleep time on a school night is 6.8 hours with a standard deviation of 1.2 hours. (Source: Data are downloaded from U.S. Census at School a) We want to test if the mean sleep time on a school night for all high school seniors in the United States is less than 7 hours. State the hypotheses of a one-sided significance test. b) ) Calculate the test statistic. I Show how to make a c) conclusion for this test, using the significance level 0.05. d) ) If your conclusion in part c) were in error, what type of error would it be? e) ) Construct a 95% confidence interval for the population mean sleep time on a school night for all high school seniors in the United States.Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 37 randomly selected people who train in groups, and finds that they run a mean of 47.7 miles per week. Assume that the population standard deviation for group runners is known to be 3.3 miles per week. She also interviews a random sample of 49 people who train on their own and finds that they run a mean of 49.4 miles per week. Assume that the population standard deviation for people who run by themselves is 4.4 miles per week. Test the claim at the 0.10 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.An analyst is conducting a hypothesis test to determine if the mean time spent on investment research is different from 3 hours per day. The test is performed at the 1% level of significance and uses a random sample of 64 portfolio managers. where the mean time spent on research is found to be 2.7 hours. The population standard deviation is 1.5 hours. What is the value of the test statistic in this case?
- Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.a group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. what is the 90% confidence interval for the mean score, u, of all students taking the test?The College Board reports that the scores on the math SAT were normally distributed with a mean of 525. A random sample of 15 students at your high school had a mean of 550 and a sample standard deviation of 105. What values of the sample mean would lead to rejection of the null hypothesis at the 0.01 level of significance?
- According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City is more than the national average, a researcher decides to do a hypothesis test, at a 1% significance level. She surveys 23 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 3.8 hours per week, and the sample standard deviation (s) is 1.1 hours. H0: μ≤3; Ha: μ>3. α=0.01 (significance level) What is the test statistic (t-value) of this one-mean hypothesis test (with σ unknown)? Round your final answer to two decimal places. Provide your answer below: $$Test Statistic =In the past, the time for Jeff's journey to work had mean 45.7 minutes and standard deviation 5.6 minutes. This year he is trying a new route. In order to test whether the new route has reduced his journey time, Jeff finds the mean time for a random sample of 30 journeys using the new route. He camies out a hypothesis test at the 2.5% significance level. Jeff assumes that, for the new route, the joumey time has a nomal distribution with standard deviation 5.6 minutes. (a) State appropriate null and alternative hypotheses for the test. (b) Determine the rejection region for the test.A school psychologist was interested in whether students in the chess club scored above or below the mean grade point average (GPA) at her school. She calculated the overall average GPA at the school to be 2.55 with a standard deviation of 0.5 and noted that the distribution was approximately normal. She then figured the average for the 30 students in the chess club. Their mean GPA was 2.76. a. Using the five steps of hypothesis testing, was the group of 30 chess club students' GPA different from students in general at this school? (Use the .05 significance level.) Be sure to sketch the distributions involved. Be sure to fully state the five steps and show ALL calculations/work. b. Additionally, explain the logic of what you did to a person who understands hypothesis testing for studies in which the sample consists of a single individual but is unfamiliar with hypothesis testing involving a sample of more than one individual. (Be sure your explanation includes a discussion of the…