A genetic experiment involving peas yielded one sample of offspring consisting of 409 green peas and 153 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% ofoffspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-valuemethod and the normal distribution as an approximation to the binomial distribution.What are the null and alternative hypotheses?O A. Ho: p#0.26О В. Но: р3D0.26H1: p>0.26H1: p#0.26ОС. Но: р30.26O D. Ho: p= 0.26H1: p>0.26H1:p<0.26ОЕ. Но: р#0.26O F. Ho: p#0.26H1: p=0.26H1: p<0.26What is the test statistic?Z =(Round to two decimal places as needed.)What is the P-value? A genetic experiment involving peas yielded one sample of offspring consisting of 409 green peas and 153 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% ofoffspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-valuemethod and the normal distribution as an approximation to the binomial distribution.(Round to four decimal places as needed.)What is the conclusion about the null hypothesis?O A. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.O B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.OC. Reject the null hypothesis because the P-value is greater than the significance level, a.O D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.What is the final conclusion?O A. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.O B. There is not sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.OC. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow.D. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow.

sample proportion = 153/562 =0.27n = 562population proportion = 0.26

What are the null and alternative hypotheses? O B. Ho: p= 0.26 O A. Ho: p#0.26 H:p>0.26 H;: p#0.26 OC. Ho: p= 0.26 O D. Ho: p= 0.26 H,:p<0.26 H: p>0.26 O E. Ho: p#0.26 OF. Ho: p#0.26 H,: p= 0.26 H;: p<0.26 What is the test statistic? z= (Round to two decimal places as needed.) What is the P.value?

What are the null and alternative hypotheses? O B. Ho: p= 0.26 O A. Ho: p#0.26 H:p>0.26 H;: p#0.26 OC. Ho: p= 0.26 O D. Ho: p= 0.26 H,:p<0.26 H: p>0.26 O E. Ho: p#0.26 OF. Ho: p#0.26 H,: p= 0.26 H;: p<0.26 What is the test statistic? z= (Round to two decimal places as needed.) What is the P.value?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Write the null and alternative hypotheses for the following example. Determine if the example is a case of a two-tailed, a left-tailed, or a right-tailed test. To test if the mean credit card debt of college seniors is less than 1000 dollars. Ho: μ = 1000 dollars, H₁: μ1000 dollars, right-tailed test Ho: μ=1000 dollars, H₁: µ1000 dollars, left-tailed test Ho: μ=1000 dollars, H₁: µ‡1000 dollars, two-tailed test
A and B please
For the statement below, write the claim as a mathematical statement. State the null and alternative hypotheses and identify which represents the claim. A laptop manufacturer claims that the mean life of the battery for a certain model of laptop is less than 9 hours. Write the claim as a mathematical statement. OA. μ=9 OD. H>9 Choose the correct null and alternative hypotheses below. OA. Ho: *9 OB. Ho: Hs9 Ha: H=9 H₂:μ>9 OB. us9 OE. *9 OD. Ho: 9 is the claim OD. The alternative hypothesis Ha: #9 is the claim O E. The null hypothesis Ho: 29 is the claim. O F. The null hypothesis Ho: μ = 9 is the claim OC. μ29 OF. μ9 Ha:μs9 ⒸF. Ho: 29 H₂:μ<9
Let’s assume the average income for all majors in the School of Engineering is $80,000. However, the chair of the Computer Science department thinks their students earn more than that. Please choose the appropriate null and alternative hypotheses if the chair wanted to test this belief. a. H0: u <=80,000 Ha: u > 80,000 b. H0: u= 80000 Ha: u not= 80000 c. H0: u >80000 Ha: u < 80000 d. H0: u >80000 Ha: < 80000 e. None of the above.
The average manufacturing work week in metropolitan Chattanooga was 40,1 hours last year. It is believed that the recession has led to a reduction in the average work week. To test the validity of this belief, the hypotheses are O* Họ 2 40.1 Hạ <40.1 ObHọ - 401 H * 40.1
For each statement, express the null hypothesis Ho and alternative hypothesis H in symbolic form. 1. The mean annual consumption of beer u in the nation's capital is less than the national mean lo- OA. Ho : µ = Ho, H1 : H # Ho OB. Ho : µ = Ho, H1 : H > Ho OC. Ho : µ = Ho, H1 : µ 98.6 98.6, H : µ 98.6, H u < 98.6 Classify the hypothesis test as two-tailed, left-tailed or right-tailed. OA. Right-tailed B. Left-tailed C. Two-tailed
Develop the analysis of variance computations for the following completely randomized design. At a = 0.05, is there a significant difference between the treatment means? %3D Treatment A В C 137 106 92 119 113 81 114 125 85 108 105 101 132 107 89 115 109 116 129 96 109 90 115 119 103 97 81 121 118 106 101 2 226.86 137.33 212.22 State the null and alternative hypotheses. Ho: : Not all the population means are equal. Ha: HA = HB = HC Hoi HA = HB = HC H: Not all the population means are equal. Ho: At least two of the population means are equal. H: At least two of the population means are different. Ho: HA = HB = Hc %3D Ha: HA + HB + HC
4
Describe type I and type II errors for a hypothesis test of the indicated claim. A furniture store claims that at least 40% of its new customers will return to buy their next piece of furniture. Describe the type I error. Choose the correct answer below. OA. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is at least 0.40, but you fail to reject Ho: p20.40. OB. A type I error will occur when the actual proportion of new customers who return to buy their next piece furniture is at least 0.40, but you reject Ho: p20.40. OC. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is no more than 0.40, but you reject Ho: p ≤ 0.40. OD. A type I error will occur when the actual proportion of new customers who return to buy their next piece f furniture is no more than 0.40, but you fail to reject Ho: p ≤0.40. Describe the type II error. Choose the correct answer…
A survey of heads of households showed the percentage of those who asked for a raise and the percentage of those who asked for a raise and the percentage who got one. Accordig to the survey, of the omen interviwed 28% asked for a raise, and of those women who asked for a raise, 45% recieved the raise. If a woman is selected at random from the survey population of women, find the following probabilites. (To three decimal places) P(woman asked for a raise) P(woman recieved raise, given she asked for one) P(woman asked for raise and recieved raise)
Less than 60% of workers indicate that they are satisfied with their job. Express the null and alternative hypotheses in symbolic form for this claim (enter as a percentage).H0:p= H1:p=