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A 60 Hz generator of 2 with inertia constant of H = 4.5 MJ/MVA is delivering active power of 1.0 pu to the infinite bus (|V∞| = 1 pu), with the generator terminal voltage of |Vt| = 1 pu. Calculate the generator internal voltage. Find the maximum power that can be transferred, the swing equation and draw power angle curves for the following conditions: (a) system healthy (b) one line shorted (3-phase) in the middle (c) one line open Draw all three power angle curves on one plot, and mark which one is which. Excitation is held constant throughout all conditions.

A 60 Hz generator of 2 with inertia constant of H = 4.5 MJ/MVA is delivering active power of 1.0 pu to the infinite bus (|V∞| = 1 pu), with the generator terminal voltage of |Vt| = 1 pu. Calculate the generator internal voltage. Find the maximum power that can be transferred, the swing equation and draw power angle curves for the following conditions: (a) system healthy (b) one line shorted (3-phase) in the middle (c) one line open Draw all three power angle curves on one plot, and mark which one is which. Excitation is held constant throughout all conditions.

Curren'S Math For Meds: Dosages & Sol
Curren'S Math For Meds: Dosages & Sol
11th Edition
ISBN:9781305143531
Author:CURREN
Publisher:CURREN
Chapter2: Multiplication And Division Of Decimals
Section: Chapter Questions
Problem 6.8P
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  • A 60 Hz generator of 2 with inertia constant of H = 4.5 MJ/MVA is delivering active power of 1.0 pu to the infinite bus (|V∞| = 1 pu), with the generator terminal voltage of |Vt| = 1 pu. Calculate the generator internal voltage. Find the maximum power that can be transferred, the swing equation and draw power angle curves for the following conditions:
  • (a) system healthy
  • (b) one line shorted (3-phase) in the middle
  • (c) one line open

Draw all three power angle curves on one plot, and mark which one is which. Excitation is held constant throughout all conditions.

jXi=j0.5 EZ8° V=1Z0° jXi=j0.5 jX'=j0.25 jX-j0.1 V;=1 Infinite bus
Transcribed Image Text:jXi=j0.5 EZ8° V=1Z0° jXi=j0.5 jX'=j0.25 jX-j0.1 V;=1 Infinite bus
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